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xclr82xtc
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this is a power calcualtion using 1 magnet pair with the turbine turning at 1 rpm..34 inch diameter rotor. i hope someone else can make sure I am at least doing it right, and i need help converting my single phase numbers to 3phase wye
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coil info
1x1x2
80 turns total, 4 rows of twenty.
center line of coil is 34 inches.
the magnets making 1 revolution per minute would pass the coils at X coils per second...lets figure out X
circumference of a 34 inch circle = 106.8 inches
divide that by 60 seconds...106.8/60= 1.78
so EVERY SECOND...the magnets travel 1.78 inches. in turn, the magnetic fields pass through the coils at the rate of 1.78 inches per second?
am i right to this point?
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there is 80 coils in 2 inches, so in 1.78inches we would have 71.2
the tesla of the magnets is .6403
the area is .75inchx2inch then change to meters squared = 0.003610meters squared
faradays law
N = -1 * (-V/ (( tesla * area meters squared)/ seconds))
71.2=-1*(-V/((.6403*.003610)/1.78)
-71.2=(-V/.00129)
.0918=V
so right now we have 71.2 turns = ..0918 v at at rate of 1 rpm...
now there is 7 coils of 80 so that's 560 total turns
divide by 71.2 =7.87
so times 7.87 time the Voltage .0918
=.722 volts per phase...
my math looks more right this time lol
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now how many feet of wire in a coil (we need to find the resistance)
wire info
Nominal Diameter: 0.10 inch
Nominal OHMS/LB. -20 Celsius: 0.0314
Feet/LB: 31.48
outersize of coil is 1 inch. 4 layers and the core is .6inches.(yes this does take into account wire size) .so the perimter for one layer of turns is (.7*4)+(.8*4)+(.9*4)+.(1*4)=2.8+3.2+3.6+4=13.6inches
now the coil is 2 inches long so we need have 20 layers...20*13.6=272inches...divde by 12=22.6 feet or wire per coil...nice. lol
ok so now we know we have 7 coils so 22.6*7 = 158.2 feet.
its 31.48 feet per lb so 158.2/31.48=5.025lbs
5.025 * .0314=.1578
so the TOTAL resistance of all seven coils is .1578ohms
_____________________________________________________
so now we know the total voltage of one phase at 1 rpm of the mill, and we know the constant resistance of the coil. (i also have the inductance of each coil but i don't think we need it.)
so with this info, we SHOULD be able to figure out the amps using ohms law. i=v/r
.722/.1578=4.578AMPS
SOOOO...per phase, at 1 rpm we have 1.29 volts and 4.578amps. kinda crappy, but hey its only turning at 1 rpm, and that's only using 1 pair of magnets, there is 15 total pairs.
________________________________________
coil info
1x1x2
80 turns total, 4 rows of twenty.
center line of coil is 34 inches.
the magnets making 1 revolution per minute would pass the coils at X coils per second...lets figure out X
circumference of a 34 inch circle = 106.8 inches
divide that by 60 seconds...106.8/60= 1.78
so EVERY SECOND...the magnets travel 1.78 inches. in turn, the magnetic fields pass through the coils at the rate of 1.78 inches per second?
am i right to this point?
___________________________________
there is 80 coils in 2 inches, so in 1.78inches we would have 71.2
the tesla of the magnets is .6403
the area is .75inchx2inch then change to meters squared = 0.003610meters squared
faradays law
N = -1 * (-V/ (( tesla * area meters squared)/ seconds))
71.2=-1*(-V/((.6403*.003610)/1.78)
-71.2=(-V/.00129)
.0918=V
so right now we have 71.2 turns = ..0918 v at at rate of 1 rpm...
now there is 7 coils of 80 so that's 560 total turns
divide by 71.2 =7.87
so times 7.87 time the Voltage .0918
=.722 volts per phase...
my math looks more right this time lol
--------------------------------------------------------------
now how many feet of wire in a coil (we need to find the resistance)
wire info
Nominal Diameter: 0.10 inch
Nominal OHMS/LB. -20 Celsius: 0.0314
Feet/LB: 31.48
outersize of coil is 1 inch. 4 layers and the core is .6inches.(yes this does take into account wire size) .so the perimter for one layer of turns is (.7*4)+(.8*4)+(.9*4)+.(1*4)=2.8+3.2+3.6+4=13.6inches
now the coil is 2 inches long so we need have 20 layers...20*13.6=272inches...divde by 12=22.6 feet or wire per coil...nice. lol
ok so now we know we have 7 coils so 22.6*7 = 158.2 feet.
its 31.48 feet per lb so 158.2/31.48=5.025lbs
5.025 * .0314=.1578
so the TOTAL resistance of all seven coils is .1578ohms
_____________________________________________________
so now we know the total voltage of one phase at 1 rpm of the mill, and we know the constant resistance of the coil. (i also have the inductance of each coil but i don't think we need it.)
so with this info, we SHOULD be able to figure out the amps using ohms law. i=v/r
.722/.1578=4.578AMPS
SOOOO...per phase, at 1 rpm we have 1.29 volts and 4.578amps. kinda crappy, but hey its only turning at 1 rpm, and that's only using 1 pair of magnets, there is 15 total pairs.