kylepetten said:Homework Statement
Calculate how much work is done when a 1150 kg car accelerates from 2 m/s to 6m/s
Homework Equations
The Attempt at a Solution
I have no idea. It seems like insufficient information to me. Please help! I am in great need as my exam is drawing near!
Thanks!
inky said:Work done=change in KE=0.5*1150(6^2-3^2)
To calculate work, you will need to use the formula W = F * d, where W is work, F is force, and d is displacement. Force can be calculated by multiplying mass (m) by acceleration (a), which can be calculated by subtracting the initial velocity (u) from the final velocity (v) and dividing by the time (t). So, the formula for work becomes W = m * (v-u)/t * d.
Yes, you can use any units as long as they are consistent. For example, if mass is given in kilograms (kg) then velocity should be in meters per second (m/s) for the equation to work correctly.
If you only have one velocity, you can still calculate work by using the formula W = (1/2) * m * v^2, where m is mass and v is velocity. This formula is commonly used for calculating kinetic energy, but can also be used to calculate work when only one velocity is known.
The work calculation is commonly used in physics and engineering to determine the amount of energy needed to move an object a certain distance. It can also be used in real life situations such as calculating the amount of work done by a machine, or the energy needed to lift an object to a certain height.
Yes, there is a difference between work and power. Work is the amount of energy needed to move an object a certain distance, while power is the rate at which work is done. Power is calculated by dividing work by time, so it is a measure of how quickly work is being done.