How to Calculate the Area of a Square Using Definite Integrals?

In summary, the area of a square with side lengths equal to the definite integral of (0.43890022*X) from 1 to 10 is471.999996.
  • #1
merven
7
0
THE AREA OF A SQUARE WITH SIDE LENGTHS EQUAL TO THE DEFINITE INTEGRAL OF (0.43890022*X) FROM 1 TO 10


please help me...

Merven
 
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  • #2
You need to show your work before you get help. What have you done with this question?
 
  • #3
ok well i posted it in the calculus forums but no one helped...
my friend is making a new website and he told me the only way i could get a peak is by solving this equation, and the reason he did this is becasue he knows far to well i can't do math, I recenty graduated HS and know nothing of calculus, that's why I am askign here, if someone would be willing to help me or to even give me crash corse because they don't think its right to just give me the answer i would be more then willing to try and learn...
thanks
Merven
 
  • #4
lol; most odd thing i have ever heard ...
but, if your story is true, i shall try and help.

I take it you would know that a square has equal length sides?
hence the area of the square is equal to the length by width (or in this case [tex] l^2 [/tex]:
[tex]A(square) = l^2[/tex]
(if u really need: http://en.wikipedia.org/wiki/Square_(geometry))

In regard to the next section, i doubt it will be even the slightest bit understandable, but none-the-less ...
A definite integral basically finds the area underneath a graph in a set region i.e. between a and b: http://en.wikipedia.org/wiki/Image:Integral_as_region_under_curve.svg
where f(x) is your function, such that: [tex]f(x) = 0.43890022x[/tex]
but for our purposes, we just want to find the numerical answer for this integral as a means of determining the area of the square.

The definite integral notation for this is:
[tex] \int_{1}^{10} {0.43890022x} [/tex]
This ican be explained as; the definite integral between 1 and 10 for the equation 0.43890022 as required.

Now we can simplify this integral and obtain a numerical answer:
[tex] \int_{1}^{10} {0.43890022x} [/tex]
[tex] = 0.43890022 \int_{1}^{10} {x} [/tex] (taken out factor)
[tex] = 0.43890022(\frac {x^2}{2}) [/tex] between 1 and 10
[tex] = 0.43890022 ((\frac {10^2}{2}) - (\frac {1^2}{2})) [/tex]
plug that into your calculator and you get:
[tex] 21.72556089 [/tex]

remember from before:
[tex]A(square) = l^2[/tex]
therefore:
[tex]A(square) = 21.72556089^2[/tex]
[tex]=471.999996[/tex]

wow that took longer than I thought, but yeh, hope this helps your cause.
You must understand that you cannot learn how to do definite integration with no understanding of basic calculus methods etc; for the parts you don't understand, just take them as facts ...
Steven
 
Last edited:
  • #5
Assuming of course that the variable of integration is X and that X varies from 1 to 10 ...
 
  • #6
hehe, yer ...

in respect to the problem given; could it be anything else??
or is that just complicating things more?
lol

Steven
 
  • #7
lol, nah it had to be X, I was just pointing out ways for the OP to get back at his supercilious friend :biggrin:
 
  • #8
haha, yeh good point and idea ...
pretty nasty form of entrance don't you think?
 
  • #9
As long as you know what 'integral means' calculus is completely irrelevant to the question. It's just a straight line graph - you can find the area by elementary means.
 
  • #10
omg if that trully is the answer, i got it right when i used one fo the calculators. but double guessed and threw it out since i had no clue. lol wow steven10137 you are my hero... lol now i have to see what he says, ill come back and post his reply :) thanks a million guys
Merven
 
  • #11
merven said:
omg if that trully is the answer, i got it right when i used one fo the calculators. but double guessed and threw it out since i had no clue. lol wow steven10137 you are my hero... lol now i have to see what he says, ill come back and post his reply :) thanks a million guys
Merven

not at all
:)
 
  • #12
lol its awsome ty again, he was shocked but gave in after i got angry LOL, thank you all again
 

What is a definite integral?

A definite integral is a mathematical concept used to find the area under a curve between two specific points on the x-axis. It involves summing up infinitely small rectangles to approximate the area of the curve.

What is the difference between a definite integral and an indefinite integral?

A definite integral has specific limits of integration, which means it will give a specific numerical value as the result. An indefinite integral does not have limits of integration, and therefore gives a general formula for the area under a curve.

How is a definite integral evaluated?

A definite integral is evaluated using the fundamental theorem of calculus, which states that the integral of a function is equal to the difference between its antiderivative evaluated at the upper and lower limits of integration.

What is the significance of definite integrals in real life?

Definite integrals have various applications in real life, such as calculating the distance traveled by an object with varying velocity, finding the total cost of a product with changing prices, and determining the average value of a function over a given interval.

Can definite integrals be negative?

Yes, definite integrals can have negative values. This occurs when the area under the curve is below the x-axis, and the integral will give a negative value as a result. This can represent quantities such as negative displacement or negative profit.

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