- #1
gemt
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i have set up an equation to get the heat transfer rate Q for a combined system where heat is transferred from a cylindrical outer wall set at 500 C. the wall heats a gas, which in turn heats a solid block of cylindrical metal positioned in the centre of the heated walls with a starting temperature of 20 C.
the equation i have is
Q=[1]\frac{}{}[/(A0/(h*Alm1))+((r*A0)/(k*A2))+(A0/(h*Alm3))+((r*A0)/(k*A4))+(A0/(h*Alm5))]*A0*[tex]\Delta[/tex]T
and it give a result of 11.3213 Watts or the situation above.
but too me this seems small?? am i right in thinking this?
also can anyone tell me how i can relate this heat transfer to time. ie. know how long it would take to heat the central metal part.
Thank you in advance.
the equation i have is
Q=[1]\frac{}{}[/(A0/(h*Alm1))+((r*A0)/(k*A2))+(A0/(h*Alm3))+((r*A0)/(k*A4))+(A0/(h*Alm5))]*A0*[tex]\Delta[/tex]T
and it give a result of 11.3213 Watts or the situation above.
but too me this seems small?? am i right in thinking this?
also can anyone tell me how i can relate this heat transfer to time. ie. know how long it would take to heat the central metal part.
Thank you in advance.