- #1
huynhtn2
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Homework Statement
When a bullet strikes a block of wood originally at rest, the bullet becomes embedded into the wood block which travels 1.70 m after the collision. If the mass of the bullet is 5.26 g and the mass of the block is 2.40 kg, what is the speed of the block immediately after the collision? The coefficient of kinetic friction between the block and the surface is 0.30.
Homework Equations
ke=0.5mv^2
Ffr= ukmg
The Attempt at a Solution
Ke = Ffriction
0.5mv^2= uk mg
v= square root (2(9.81)(0.3))
v= 2.43 m/s
i don't know what to do with the 1.70 m distance