Heat Transfer Coefficient for Ice Melting Time

In summary, a 100 gram sphere of ice at 0 C is placed in a liter of water at 30 C, which contains 30000 calories. The ice absorbs 8000 calories, causing the final water temperature to be 20 C. Assuming uniform water temperature and insulation from the surroundings, it would take approximately 13.7 hours for the ice to melt. This can be calculated using the heat transfer coefficient, which is affected by the surface area of the sphere and the temperature difference between the water and ice.
  • #1
morrobay
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Homework Statement


One liter of water at 30 C ( 30000 calories )
100 gram (100 cc ) sphere of ice at 0 C is in center of water volume.
The ice will absorb 8000 cal melting and final water temp = 22000 cal/ 1100 g = 20 C
Assuming mixing and uniform water temp during melting ,and vessel is insulated from
surroundings , how long for ice to melt ?

Homework Equations


Heat Transfer Coefficient: for phase changes between a fluid and solid
h = q/A delta T

q = cal/sec
h = cal/sec/M2 C for ice .523
A= surface area sphere = .01034 M2
delta T = 30 C

The Attempt at a Solution


This is difficult since delta T and A are both going to 0
For initial conditions only q = (.523 cal/sec/M2 C) (.01034 M2)30 C
q= .162 cal/sec , 8000 cal/.162 cal/sec = 13.7 hrs
 
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  • #2
morrobay said:

Homework Statement


One liter of water at 30 C ( 30000 calories )
100 gram (100 cc ) sphere of ice at 0 C is in center of water volume.
The ice will absorb 8000 cal melting and final water temp = 22000 cal/ 1100 g = 20 C
Assuming mixing and uniform water temp during melting ,and vessel is insulated from
surroundings , how long for ice to melt ?


Homework Equations


Heat Transfer Coefficient: for phase changes between a fluid and solid
h = q/A delta T

q = cal/sec
h = cal/sec/M2 C for ice .523
A= surface area sphere = .01034 M2
delta T = 30 C

The Attempt at a Solution


This is difficult since delta T and A are both going to 0
For initial conditions only q = (.523 cal/sec/M2 C) (.01034 M2)30 C
q= .162 cal/sec , 8000 cal/.162 cal/sec = 13.7 hrs

Attn Moderator: Since the physicists are not able to answer this , would you please
move it to the Other Sciences section so the Chemists and Engineers can look at it.
Thank you.
 

1. What is the Heat Transfer Coefficient for Ice Melting Time?

The Heat Transfer Coefficient for Ice Melting Time is a measure of how quickly heat is transferred to ice, causing it to melt. It is typically represented by the symbol "h" and has units of watts per square meter per Kelvin (W/m²K).

2. How is the Heat Transfer Coefficient for Ice Melting Time calculated?

The Heat Transfer Coefficient for Ice Melting Time is calculated by dividing the rate of heat transfer by the temperature difference between the ice and the surrounding environment. It can also be calculated by dividing the thermal conductivity of the material by the thickness of the ice layer.

3. What factors affect the Heat Transfer Coefficient for Ice Melting Time?

The Heat Transfer Coefficient for Ice Melting Time can be affected by several factors, including the properties of the ice (such as thickness and density), the properties of the surrounding environment (such as temperature and humidity), and the presence of any insulating materials or barriers.

4. How does the Heat Transfer Coefficient for Ice Melting Time impact ice melting in real-world scenarios?

The Heat Transfer Coefficient for Ice Melting Time is an important factor in understanding how quickly ice will melt in different situations. For example, a higher coefficient means that heat is transferred more efficiently, resulting in faster melting. This can be useful for predicting ice melt rates on roads, bridges, or other structures.

5. Can the Heat Transfer Coefficient for Ice Melting Time be changed or controlled?

The Heat Transfer Coefficient for Ice Melting Time can be influenced by manipulating the surrounding environment or using insulating materials. For example, increasing the temperature of the environment or adding a layer of insulation can decrease the coefficient and slow down ice melting. However, the coefficient itself is a property of the materials and cannot be directly changed.

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