- #1
yavanna
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If [itex]p[/itex] is a prime and [itex]a[/itex] an integer coprime with [itex]p[/itex], why is
[itex]a^{\frac{p-1}{2}}\equiv -1 mod p[/itex] ?
[itex]a^{\frac{p-1}{2}}\equiv -1 mod p[/itex] ?
The statement "Proof of a^{\frac{p-1}{2}}=-1 mod p" is a mathematical proof that relates to the properties of prime numbers. It states that for any prime number p and any integer a that is not divisible by p, the expression a^{\frac{p-1}{2}} is congruent to -1 modulo p.
This proof is important because it is a fundamental result in number theory and has many applications in cryptography and other areas of mathematics. It also helps to deepen our understanding of prime numbers and their properties.
The exponent \frac{p-1}{2} is significant because it is half of the value p-1, which is the Euler totient function of p. This function represents the number of positive integers less than p that are coprime to p. In other words, it represents the number of elements in the multiplicative group of integers modulo p.
No, this proof is specifically for prime moduli. The statement is not true for non-prime moduli, as there may not exist a primitive root that satisfies the congruence relation.
This proof is related to Fermat's little theorem, which states that for any prime number p and any integer a, a^{p-1} is congruent to 1 modulo p. This proof can be seen as a generalization of Fermat's little theorem, as it shows that a^{\frac{p-1}{2}} is congruent to -1 modulo p for any non-zero integer a, rather than just for a=1.