Mass Defect to calculate the stability of a nucleus

In summary: So if you want to calculate the binding energy of a nucleus, you start by subtracting the mass defect from the total mass of the nucleus.
  • #1
4everphysics
19
0
This is just a simple conceptual question.

When we try to calculate a nuclear binding energy of some nucleus,
we get the mass defect(del M) and find the binding energy by using
(del M)c^2 right?

Well, what I do not understand is this.
For instance, let's take a formation of a flourine-19.
Flourine formation(out of neutrons and protons) would be exothermic because del M is negative, but why would energy be released to the surrounding if also the same amount of energy is being used to bind the nucleus together?

Meaning, if some (x)J amount of energy is being used as a binding energy of flourine, the mass would convert to that energy and will be thus used to bind the flourine nucleus (and if that energy is being hold onto by the nucleus as a binding energy, it should not be released to the surrounding. no?)

I hope I have phrased my question right.
Thank you.
 
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  • #2
Binding energy is energy required to break something apart, not to put something together. I know it sounds backwards, but it is consistent with classical picture of holding things together. If there is a force pulling two objects together, you must do work to pull them apart. Conversely, you can make them do work by letting them pull together closer. So the binding energy is released when the nucleus is formed, not absorbed.
 
  • #3
So if the nucleus forms a "rope" when it is formed by converting the mass to the "rope",
why is seemingly "additional" energy released to the environment as well? when it is used up by forming the "rope"?
 
  • #4
That's just not how it works. Picture two powerful magnets sticking to each other. The sound they make as they smash into each other is basically the release of the binding energy. There is nothing there that requires additional energy.
 
  • #5
Magnets that snap together have opposite charge. Maybe the binding energy is the energy required to hold together like charged nucleons...
 
  • #6
Look at it this way. The mass defect in a hydrogen atom is -13.6 eV, relative to a free proton and electron.
 

1. What is mass defect and how is it related to the stability of a nucleus?

Mass defect is the difference between the mass of an atom's nucleus and the combined masses of its individual protons and neutrons. This difference is a result of the binding energy that holds the nucleus together. A lower mass defect indicates a more stable nucleus.

2. How is mass defect calculated?

Mass defect is calculated by subtracting the mass of the individual protons and neutrons in a nucleus from the total mass of the nucleus. The resulting difference is then converted into energy using Einstein's famous equation, E=mc^2.

3. What factors can affect the mass defect and stability of a nucleus?

The number of protons and neutrons in a nucleus, as well as the specific arrangement of these particles, can affect the mass defect and stability of a nucleus. Additionally, the strong nuclear force, which is responsible for holding the nucleus together, also plays a role in determining the stability of a nucleus.

4. How does the mass defect affect the energy released during nuclear reactions?

The greater the mass defect, the more energy is released during a nuclear reaction. This is because the conversion of mass into energy is directly proportional to the mass defect.

5. Why is it important to understand mass defect in nuclear physics?

Understanding mass defect is crucial in nuclear physics as it helps scientists predict the stability and behavior of different nuclei, as well as the energy released during nuclear reactions. This knowledge is essential for various applications, such as nuclear power generation and nuclear medicine.

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