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Fiddle
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Homework Statement
http://img12.imageshack.us/img12/1176/img20120713190506.jpg
Homework Equations
V[itex]_{C}[/itex]' = dv/dt
I[itex]_{L}[/itex]' = di/dt
The Attempt at a Solution
I did KCL at the centre node:
I[itex]_{L}[/itex] + i[itex]_{2}[/itex] = [itex]\frac{V_{C}'}{5}[/itex]
(Vc'/5 is basically the current coming from the capacitor line to the centre node (from equation ic = Cdv/dt)
Re-arranging you get i2 = [itex]\frac{V_{C}'}{5}[/itex] - I[itex]_{L}[/itex]
I then look at the inductor voltage next, basically the inductor voltage is the voltage across the 10ohm resistor at the top minus the voltage across the capacitor, so:
V[itex]_{L}[/itex] = 10i[itex]_{1}[/itex] - V[itex]_{C}[/itex]
Now I substitute this into the standard equation for an inductor:
I[itex]_{L}[/itex]' = [itex]\frac{V_{L}}{L}[/itex]
Which gives us 10i[itex]_{1}[/itex] - V[itex]_{C}[/itex] = 2.5I[itex]_{L}[/itex]'
or i[itex]_{1}[/itex] = [itex]\frac{I_{L}'}{4}[/itex] + [itex]\frac{V_{C}}{10}[/itex]
Altogether now in state-space representation:
http://img824.imageshack.us/img824/3282/img20120713191406.jpg
I'm not sure I've done this correctly because there is no Ia (Current source) or Va(voltage source) from the circuit diagram involved, also I'm not sure if my final expression in matrix form is correct.
Any help is appreciated.
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