- #1
iRaid
- 559
- 8
Homework Statement
[tex]y'+ycot(x)=cos(x)[/tex]
Homework Equations
The Attempt at a Solution
First I found the integrating factor:
[tex]\rho (x)=e^{\int cot(x)dx}=e^{ln(sinx)}=sinx[/tex]
Plug into the equation for first order DE...
[tex]\int \frac{d}{dx} ysinx=\int cosxsinx dx[/tex]
End up with:
[tex]ysinx=\frac{-cos^{2}x}{2}+C\\y=\frac{-cosxcotx}{2}+\frac{C}{sinx}[/tex]
I think that's wrong tho..