The quantum based calculation of the cosmological constant

In summary, the conversation discusses the Higgs field and its contribution or lack thereof to the vacuum energy density. It is important to distinguish between the Higgs field, which has a nonvanishing vacuum expectation value but has effectively zero vacuum energy, and a dark energy candidate which must have nonzero vacuum energy to contribute to the stress-energy tensor for accelerated expansion. The conversation also touches on the idea of supersymmetry and its potential role in cancelling out vacuum energy contributions from different fields. Overall, the question remains unanswered and requires a theory of quantum gravity to fully understand.
  • #1
salvestrom
226
0
I nearly referred to it as infamous in the title. Unfair?

My question is this: why did they add up the combined energy of all the fields when only the Higgs field would be active in void space (I use this term to refer to the spaces between filaments, does it have its own name or is it usually just called intergalactic space?)?

An extension of this question is why do they consider each force to have its own energy field. Isn't it simpler to assume they use a single source of energy, which reacts depending on how it is interacted with? I see a similarity here with String Theory duality.

Should this be in the Quantum Mechanics forum? lol.

If dark energy is consider to also come from the vaccum, wouldn't that tie in with the Higgs Field having a non-zero expectation value? I understand the purpose of the Higgs Field. Breaking symmetry, imparting mass. Usually, descriptions of it talk in terms as if the Higgs field is still operating today, i.e. that we and our planet gain their mass as a sort of ongoing process. I tend to end up thinking about what all this "excess" energy is doing out in deep space with no matter to wrestle with.

I appreciate that when confronted with something that seems obvious, ones first reaction should be to determine if one hasn't simply misunderstood something along the way. That's where you lot come in ;). Something beyond "no" and before "wall-of-maths-crits-you-for-INFINITE-damage". (That one's for Drakkith. He's going to glare at the screen, annoyed when he reads this post, I can feel it.)
 
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  • #2
It's important to make the distinction between the Higgs field, which has a nonvanishing vacuum expectation value, [itex]\langle \phi \rangle = v[/itex] but has vanishing vacuum energy, and the type of scalar field that would be a dark energy candidate. Dark energy candidates must have nonzero vacuum energy, and this energy must dominate the stress-energy tensor for accelerated expansion to take place. Since the Higgs has effectively zero vacuum energy, it does not contribute (as a zero mode) to the stress-energy tensor.

With regards to summing up all particle species in the computation of the cosmological constant, this is done because all fields have vacuum fluctuations. The only difference between the Higgs, and say the electron field, is that the Higgs fluctuates about [itex]\langle \phi \rangle = v[/itex] whereas the electron field fluctuates about [itex]\langle \psi \rangle= 0[/itex].
 
  • #3
bapowell said:
It's important to make the distinction between the Higgs field, which has a nonvanishing vacuum expectation value, [itex]\langle \phi \rangle = v[/itex] but has vanishing vacuum energy, and the type of scalar field that would be a dark energy candidate. Dark energy candidates must have nonzero vacuum energy, and this energy must dominate the stress-energy tensor for accelerated expansion to take place. Since the Higgs has effectively zero vacuum energy, it does not contribute (as a zero mode) to the stress-energy tensor.

With regards to summing up all particle species in the computation of the cosmological constant, this is done because all fields have vacuum fluctuations. The only difference between the Higgs, and say the electron field, is that the Higgs fluctuates about [itex]\langle \phi \rangle = v[/itex] whereas the electron field fluctuates about [itex]\langle \psi \rangle= 0[/itex].

That was way more straightforward than I expected. Thanks =D.
 
  • #4
bapowell said:
ISince the Higgs has effectively zero vacuum energy, it does not contribute (as a zero mode) to the stress-energy tensor.
It seems to me that that begs the question. Is it zero because its value is defined so that its minimum will be zero?

The only way that we are going to get a solution to this problem is by getting a theory of quantum gravity. Let's see what the problem is.

Take a bosonic field. Its vacuum energy is
[itex]E = g\sum_{\mathbf{k}} \frac12\omega_{\mathbf{k}}[/itex]
A fermionic field has the sign reversed. g = degeneracy, k is a mode momentum, w is the mode energy. Taking the continuum limit, this formula gives the energy density:
[itex]\rho = g\int \frac{d^3 k}{(2\pi)^3} \frac12\omega_k[/itex]

Thus, [itex]\rho \sim E_{max}^4[/itex], where Emax is the maximum energy integrated over.

But what is Emax? For quantum gravity, the appropriate energy scale is the Planck mass, and it would make the Universe's size the Planck length. But we don't live in that kind of Universe, so something must be wrong. The observed value is about 10-120[/sub] this value, implying Emax ~ 0.01 eV.

Supersymmetry seems to help. In supersymmetry, # bosonic modes = # fermionic modes, so we should get cancellation. But supersymmetry is broken, and a likely energy scale is a few TeV. That still produces an excessively-high cosmological constant, by a factor of 1058 (3 TeV vs. 0.01 eV).

So we don't know what's producing this almost-but-not-quite cancellation.
 
  • #5
You misread my post. I point out that it does not contribute "as a zero mode" to the stress tensor. In other words, its potential energy is zero in the vacuum state. Of course, Higgs fluctuations about this vacuum state contribute to the cosmological constant.

The distinction I was making in reponse to the OP was between a field having a nonzero VEV and a nonzero vacuum energy. The Higgs has the former, a dark energy candidate has the latter.
 
  • #6
The Higgs field could also contribute to the vacuum energy density.

I'll work out the integral above. It's for the noninteracting case, and I don't know how to do it for interactions. For large k, I find
[itex]\rho \sim \frac{g}{4(2\pi)^3}\left(k^4 + k^2m^2 + \frac18m^4 - \frac12m^4\log\frac{2k}{m}\right)[/itex]

So to cancel, the sums of all these must cancel: P*g, m2*P*g, m4*P*g, m4*log(m)*P*g, where the fermionic parity P is +1 for bosons and -1 for fermions. The supersymmetric sum rule is that the sum of P*g cancels, but supersymmetry supplies no constraints on the other sums.

Let's now calculate the Higgs-field vacuum energy from its potential. Let
[itex]V(\phi) = V_0 + \frac12V_2\phi^2 + \frac14V_4\phi^4[/itex]
The minimum is at
[itex]\phi = \sqrt{- \frac{V_2}{V_4}}[/itex]
implying V2 < 0, and it yields
[itex]V = V_0 - \frac14\frac{V_2^2}{V_4}[/itex]
 
  • #7
bapowell said:
You misread my post. I point out that it does not contribute "as a zero mode" to the stress tensor. In other words, its potential energy is zero in the vacuum state. Of course, Higgs fluctuations about this vacuum state contribute to the cosmological constant.

The distinction I was making in reponse to the OP was between a field having a nonzero VEV and a nonzero vacuum energy. The Higgs has the former, a dark energy candidate has the latter.

Does this mean that the dark energy is producing more than it consumes, with the excess causing expansion, as where the other fields have a balanced diet? It seems very odd that the Higgs field should average out at non-zero. Is this predicted to be positive or negative? Actually, is this non-zero value precisely what gives the other particles mass? In other words if the VEV were 0 the field wouldn't actually do its job?
 
  • #8
salvestrom said:
Does this mean that the dark energy is producing more than it consumes, with the excess causing expansion, as where the other fields have a balanced diet?
I don't know what you mean by this. Fields don't consume anything.
It seems very odd that the Higgs field should average out at non-zero. Is this predicted to be positive or negative? Actually, is this non-zero value precisely what gives the other particles mass? In other words if the VEV were 0 the field wouldn't actually do its job?
The nonzero VEV is what gives other particles mass; the Higgs taking on a nonzero VEV is precisely how the Higgs breaks the symmetry of the theory.
 
  • #9
lpetrich said:
[itex]V = V_0 - \frac14\frac{V_2^2}{V_4}[/itex]
Which is equal to what? I think you'll find that it vanishes in the Standard Model and MSSM.
 
  • #10
bapowell said:
I don't know what you mean by this. Fields don't consume anything.

The nonzero VEV is what gives other particles mass; the Higgs taking on a nonzero VEV is precisely how the Higgs breaks the symmetry of the theory.

Fields create and annihilate virtual particles. They give out and take back. Produce and consume.

Your second statememnt seems to be confirming what I said in the second quote.
 
  • #11
salvestrom said:
Fields create and annihilate virtual particles. They give out and take back. Produce and consume.
Ah I see. The field driving the accelerated expansion is doing so on account of its nonzero vacuum energy, not through particle excitations. Its unique behavior stems from the bizarre nature of vacuum energy -- it has a constant density. As a comoving volume filled with dark energy expands, energy is created.
 
  • #12
bapowell said:
Which is equal to what? I think you'll find that it vanishes in the Standard Model and MSSM.
Energy density for the Higgs vacuum value:
[itex]\rho = V(\sqrt{-V_2/V_4}) = V_0 - \frac14\frac{V_2^2}{V_4}[/itex]

Is there any justification within the Standard Model or the MSSM for fixing V0 so that this quantity is zero?

I mean by the energy density the quantity that contributes to the energy-momentum tensor Tij in Einstein's equation

Gij = K*Tij

where Gij is the Einstein curvature tensor.

For a metric gtt = 1, gtx = 0, gxy = - dxy (Kronecker delta), and in a frame that moves with the matter-energy, the energy-momentum tensor is
Ttt = (energy density), Ttx = 0, Txy = (pressure)*dxy
or in covariant notation,
[itex]T^{ij} = (\rho + P)u^iu^j - (u_ku^k)Pg^{ij}[/itex]
 
  • #13
OK, I see your point. I guess I'm arguing that the Higgs has zero effective vacuum energy because we see no evidence for it. I make the distinction that the tree-level vacuum energy density of a scalar field gravitates in a way that we understand (e.g. inflation), while vacuum fluctuations might not (e.g. cosmological constant problem). Of course, the other option is that all vacuum energy gravitates the same and that we don't understand the cancellations.
 
  • #14
The Higgs vacuum value of the cosmological constant, without cancellations, is around 1054 times the observed value. So as you say, we don't understand where this cancellation might come from.

A dynamic effect could do it, like Quintessence (physics) - Wikipedia Many quintessence models have tracker behavior, where it tracks the matter density.

Quintessence ("fifth stuff") or aether was the traditional celestial element, in additional to the traditional four terrestrial elements. I once saw this identification of the terrestrial ones with the major constituents of the Universe:
Earth = Baryonic matter
Water = Dark matter
Air = Neutrinos
Fire = Photons
 

1. What is the cosmological constant?

The cosmological constant is a term in the equations of general relativity, proposed by Albert Einstein, that represents the energy density of the vacuum of space. It is also known as the "dark energy" of the universe.

2. How does quantum theory relate to the calculation of the cosmological constant?

In quantum theory, particles and fields can fluctuate and have an inherent uncertainty. These fluctuations can contribute to the energy density of the vacuum, which affects the cosmological constant. Therefore, quantum theory is used to calculate the value of the cosmological constant.

3. Why is the calculation of the cosmological constant important?

The value of the cosmological constant has a significant impact on our understanding of the universe and its evolution. It is also a crucial parameter in cosmological models and can help us determine the fate of the universe.

4. How do scientists calculate the cosmological constant using quantum theory?

Scientists use mathematical equations and models based on quantum theory to calculate the energy density of the vacuum and its contribution to the cosmological constant. These calculations involve complex mathematical techniques and are constantly being refined and improved.

5. What is the current status of the quantum based calculation of the cosmological constant?

The quantum based calculation of the cosmological constant is an ongoing and active area of research. Scientists are constantly working to improve and refine the calculations, as well as to compare them with observational data from the universe. There is still much debate and uncertainty surrounding the exact value of the cosmological constant, but progress is being made in understanding this fundamental aspect of our universe.

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