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Struggling
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hi I am having trouble with finding the neutral axis and second moment of a T-beam.
here are the measurements of the beam:
http://img354.imageshack.us/img354/8648/beam6xl.jpg
i understand to find the neutral axis you divide the beam into 2 rectangles but iam having problem finding the thickness of the bottom rectangle of the t-beam. how can i find the neutral axis if i can't find the width of the bottom rectangle, because i can't find the area of it. iam totally stuck.
also calcutale the second moment of area
for a member with a rectangular cross section bent about the z axis,
Izz =(1/12)bd^3
to determine the second moment of area of a cross section made of a number of different shapes the parallel axis theorem is used.
Iaa = Izz + Ay^2
what i did was:
Izz = (1/12)6.4(38.1)^3
= 29496.72
but it doesn't make sense i was going to insert this into Iaa= Izz + Ay^2 to get the second moment of the vertical.
can someone please help
here are the measurements of the beam:
http://img354.imageshack.us/img354/8648/beam6xl.jpg
i understand to find the neutral axis you divide the beam into 2 rectangles but iam having problem finding the thickness of the bottom rectangle of the t-beam. how can i find the neutral axis if i can't find the width of the bottom rectangle, because i can't find the area of it. iam totally stuck.
also calcutale the second moment of area
for a member with a rectangular cross section bent about the z axis,
Izz =(1/12)bd^3
to determine the second moment of area of a cross section made of a number of different shapes the parallel axis theorem is used.
Iaa = Izz + Ay^2
what i did was:
Izz = (1/12)6.4(38.1)^3
= 29496.72
but it doesn't make sense i was going to insert this into Iaa= Izz + Ay^2 to get the second moment of the vertical.
can someone please help
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