- #1
g.sharm89
- 3
- 0
Hey. I am having a hard time solving this problem.
(x^2)y' + 2xy = 5y^4
I get as far as simplifying to
y' = [(5y^4)/(x^2)] - 2y/x
Then use v: y/x and y: vx & y': v'x + v
And get
v'x + v = [5(v^4)(x^2)] - 2v
And then I get lost. Any help would be appreciated. Thanks!
(x^2)y' + 2xy = 5y^4
I get as far as simplifying to
y' = [(5y^4)/(x^2)] - 2y/x
Then use v: y/x and y: vx & y': v'x + v
And get
v'x + v = [5(v^4)(x^2)] - 2v
And then I get lost. Any help would be appreciated. Thanks!