Calculating the pH of 350L of Sulfuric Acid (H2SO4)

[raviyank]

sulphuric has 2 protons.

so ph =-log(0.0004)

=-(log4-4)
=-(0.6021-4)
=3.3979

 

[raviyank]

1 hydrogen has 1 proton but in sulphuric there are 2 hydrogen

 

[Borek]

sulphuric has 2 protons.

so ph =-log(0.0004)

=-(log4-4)
=-(0.6021-4)
=3.3979

This is wrong, please reread the question.

And read forum rules, giving final answers is against them. Not to mention giving wrong final answers.

 

[chawki]

Hello Borek
please check this:

C_A*V_A=C_B*V_B
2*10^-4*350=m_B/40
m_B=2*10^-4*350*40 = 2.8g

That's it ?

 

[Borek]

2.8g of NaOH it is.

 

[chawki]

2.8g of NaOH it is.

Yay :tongue2: thank you Borek