How to calculate mass of fuel needed to escape Earth gravity vs. Mars gravity

In summary, it would take more fuel to launch a rocket from Mars than it would from Earth due to the higher gravity on Mars.
  • #1
jhochstein
2
0
I am trying to determine approximately how much fuel it would take to launch a bi-propellant rocket from Mars and Earth such that they escape each planet's respective gravity. Unfortunately, my orbital mechanics is a little rusty, and the solution I'm getting does not make much sense. Here's what I've been trying - hopefully someone can point out my error:

Assumptions:
Earth escape velocity (Vesc,e) = 11 200 m/s
Mars escape velocity (Vesc,m) = 5 027 m/s
Gravity of Earth (ge) = 9.81 m/s2
Gravity of Mars (gm) = 3.71 m/s2
Specific Impulse of a bipropellant liquid rocket (Isp) = 450 s
Dry mass of rocket (structure + payload) = Mdry
Mass of rocket fuel = Mfuel
Wet mass of rocket = Mwet

Okay, using the Rocket Equation we have

deltaV = Vexhaust * ln(Mwet/Mdry) = Vexhaust * ln((Mdry + Mfuel)/Mdry)

Therefore, deltaV/Vexhaust = ln(Mdry + Mfuel)/Mdry)

And, e(deltaV/Vexhaust) = e(ln(Mdry + Mfuel)/Mdry)) = (Mdry + Mfuel)/Mdry)

Mdry * e(deltaV/Vexhaust) - Mdry = Mfuel

Therefore, Mfuel = Mdry(e(deltaV/Vexhaust) - 1)

If Vexhaust = Isp * g then Mfuel = Mdry(e(deltaV/Isp*g) - 1)

Assuming that the deltav equals the escape velocity, the fuel required to escape Earth gravity is

Mfuel,earth = Mdry(e(11200/(450*9.81)) - 1) = 5.8965 * Mdry

and,

Mfuel,mars = Mdry(e(5027/(450*3.71)) - 1) = 7.1828 * Mdry

This would seem to say that more fuel is required to escape Mars than is needed to escape Earth, which seems completely incorrect. Can someone please point out to me where I've gone wrong?
 
Astronomy news on Phys.org
  • #2
Your specific impulse for both rockets was determined using Earth's gravity. Then you used your fuel rate using Earth's gravity for the Earth rocket and Mar's gravity for the Mars rocket.

The units for specific impulse (sec) and fuel rate (N/sec or lbs/sec) are totally artificial and are obtained by tossing 'g' into the equations for each. (Actually, it's just a unit conversion.)

In reality, rockets are based on the simple principle of conservation of momentum. The mass times velocity of the fuel tossed out the back equals the change in momentum of the rocket.

Mass doesn't change regardless of where you are. If you realize its the mass that really matters and that the 'g' tossed into each equation should cancel out, then you'll realize you need to use the same 'g' no matter which planet you're talking about.

It does seem a strange way of doing things. But specific impulse is more a measure of how efficient the fuel process is than anything else. In the end, you do get a force from your thrusters measured in the proper units for force (Newtons or pounds).

And I realize you didn't calculate the specific impulse - that it was given to you, but I guarantee 'g' was used in coming up with the specific impulse and the 'g' was 9.8 m/sec^2. (Which is why "If Vexhaust = Isp * g..." is true; you're pulling the 'g' back out of your specific impulse. You need to make sure you're pulling out the same 'g' that originally went in.) And, in reality, that specific impulse will be constantly changing, so be glad they just gave it to you, even if it leads to some confusion (as the pressure in the fuel tanks decrease, the specific impulse will decrease while, conversely, as the temperature builds up due to the chemical reactions, the specific impulse will increase - think PV=NRT).

The working versions of equations for things are always the easiest for doing calculations, but tend to use some shortcuts that obscure what's really happening, so I can see why you would make the assumptions you did.

Specific impulse is the velocity of the fuel coming out of the thruster divided by g. Fuel rate is the mass of the fuel being used per second times g. The g just cancels out, leaving mv. Of course, the rate you're using up fuel also determines the rate that the rocket is losing mass, which affects the acceleration from your thrusters, hence some of the other parameters in your equations. A lot of things are being rolled into just a few equations.
 
Last edited:
  • #3
Thank you, BobG. I appreciate the clarification.
 

1. How do I calculate the mass of fuel needed to escape Earth's gravity?

To calculate the mass of fuel needed to escape Earth's gravity, you will need to use the equation for escape velocity: V = √(2GM/R), where G is the gravitational constant, M is the mass of Earth, and R is the distance from the center of Earth to the spacecraft's starting point. Once you have calculated the escape velocity, you can use the rocket equation (m0/m1 = e^(ΔV/ve)) to determine the mass of fuel needed, where m0 is the initial mass of the spacecraft, m1 is the final mass after fuel is burned, ΔV is the change in velocity needed to escape Earth's gravity, and ve is the specific impulse of the rocket engine.

2. How is the calculation for escaping Mars' gravity different from Earth's?

The calculation for escaping Mars' gravity is similar to Earth's, but there are a few key differences. The main difference is that the mass of Mars and the distance from its center to the spacecraft's starting point must be used in the escape velocity equation. Additionally, the specific impulse of the rocket engine may be different due to the different atmospheric conditions on Mars.

3. What factors affect the amount of fuel needed to escape Earth's gravity?

The amount of fuel needed to escape Earth's gravity is affected by several factors. These include the mass of the spacecraft, the specific impulse of the rocket engine, the distance from Earth's center to the spacecraft's starting point, and the desired escape velocity. Additionally, external factors such as atmospheric conditions and gravitational pull from other celestial bodies may also play a role.

4. Can the mass of the spacecraft affect the amount of fuel needed to escape Earth's gravity?

Yes, the mass of the spacecraft does affect the amount of fuel needed to escape Earth's gravity. The more massive the spacecraft, the more fuel will be needed to provide enough thrust to overcome Earth's gravitational pull. This is why spacecraft are designed to be as lightweight as possible in order to minimize the amount of fuel needed for a successful launch.

5. Why is it important to accurately calculate the mass of fuel needed to escape Earth's gravity?

Accurately calculating the mass of fuel needed to escape Earth's gravity is crucial for a successful launch. If too little fuel is used, the spacecraft may not have enough thrust to escape Earth's gravitational pull and could potentially become stuck in orbit. On the other hand, if too much fuel is used, the spacecraft may become too heavy and again, may not be able to escape Earth's gravity. Properly calculating the mass of fuel needed helps ensure a safe and successful launch into space.

Similar threads

Replies
37
Views
10K
  • Sci-Fi Writing and World Building
Replies
4
Views
1K
Replies
43
Views
5K
Replies
31
Views
4K
  • MATLAB, Maple, Mathematica, LaTeX
Replies
1
Views
1K
  • Astronomy and Astrophysics
Replies
2
Views
9K
  • Introductory Physics Homework Help
Replies
14
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
1K
Replies
86
Views
4K
  • Introductory Physics Homework Help
Replies
14
Views
1K
Back
Top