E/M should be constant


by nil1996
Tags: constant, e or m, emc2
nil1996
nil1996 is offline
#1
Nov29-13, 07:43 PM
P: 296
As the speed of light is constant in the universe, E/M should be constant.
Suppose that in some corner of universe mass is being converted in energy. So there must be some another corner of universe where mass is being converted into energy at the same time.Is my argument correct??
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ZapperZ
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#2
Nov29-13, 08:06 PM
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Quote Quote by nil1996 View Post
As the speed of light is constant in the universe, E/M should be constant.
Suppose that in some corner of universe mass is being converted in energy. So there must be some another corner of universe where mass is being converted into energy at the same time.Is my argument correct??
Sorry, but this makes no sense.

You are confusing an equation that describes the conversion of one to another with a conservation law. That equation is not a conservation law just because c is a constant.

Zz.
sigma_
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#3
Nov29-13, 08:19 PM
P: 32
E=mc^2 is an equation that describes the constant of proportionality between an object's rest mass, and the energy that mass contains.

The sum total of mass and energy in the universe has to remain unchanged by the first law of thermodynamics, but mass energy equivalence does not indicate that there must be a certain proportion between the two when you sum all the mass and energy in the universe.

nil1996
nil1996 is offline
#4
Nov29-13, 08:30 PM
P: 296

E/M should be constant


thanks,
i was thinking that E represents energy of universe while M mass of universe ant that equation works as conservation of energy.
sigma_
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#5
Nov29-13, 08:35 PM
P: 32
Quote Quote by nil1996 View Post
thanks,
i was thinking that E represents energy of universe while M mass of universe ant that equation works as conservation of energy.
E would represent all the energy due to all the mass in the universe, not the total energy in the universe. Hope that makes sense
nil1996
nil1996 is offline
#6
Nov29-13, 08:43 PM
P: 296
Quote Quote by sigma_ View Post
E would represent all the energy due to all the mass in the universe, not the total energy in the universe. Hope that makes sense
yes got now
Thanks


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