Frictionless Bead Sliding Down A Parabola

In summary, a frictionless bead sliding down a parabola is a theoretical concept used in physics to model the motion of a particle with no frictional forces acting on it. It is relevant to real-world situations as it can be used to understand the behavior of objects in situations with negligible friction, such as in space or in laboratory experiments. The key factors that affect this motion include the initial position and velocity of the bead, the shape of the parabola, and the acceleration due to gravity. The position of the bead changes continuously as it follows the shape of the curve, moving faster as it gets closer to the bottom and slowing down as it reaches the top. Real-world applications of this concept include its use in designing roller coasters
  • #1
devon cook
6
0

Homework Statement


It seems simple, doesn't it? A bead starts from (0,1/2) and simply slides down the parabola y=(1/2)(x-1)2 under gravity. The problem is to get its position rel. to origin in terms of time, ie.
r = [x(t),y(t)]. Anyone into this?


Homework Equations


y' = x-1 = tan A where A is angle tangential veloc. (v) (and tang. accel.(a)) makes with x axis.
a = -g sin A .


The Attempt at a Solution


For starters, can I say that sin A = -(x-1)/sqr(1+(x-1)^2) ?
 
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  • #2
What quantities do you think are conserved? Can you use them?
 
  • #3


I find this problem intriguing and worth exploring. The concept of a frictionless bead sliding down a parabola under the influence of gravity presents an interesting scenario for studying motion and dynamics.

To approach this problem, we can use the basic principles of motion and Newton's laws of motion. The equation y=(1/2)(x-1)^2 represents the parabolic path of the bead, and we can use this to determine the position of the bead at any given time.

Firstly, we can consider the tangential velocity and acceleration of the bead. As mentioned in the problem, y' = x-1 = tan A, where A is the angle that the velocity vector makes with the x-axis. This means that the tangential velocity of the bead is given by v = dx/dt = (x-1)dx/dt. Similarly, the tangential acceleration can be expressed as a = d^2x/dt^2 = (x-1)d^2x/dt^2.

Using the equation of motion, we can determine the position of the bead as a function of time. r = [x(t), y(t)] = [x(t), (1/2)(x(t)-1)^2]. This equation will give us the position of the bead at any given time.

To further analyze the motion of the bead, we can also consider the forces acting on it. The only force acting on the bead is the gravitational force, given by F = mg. This force is always acting vertically downwards, and we can use it to determine the acceleration of the bead along the parabolic path.

In conclusion, the problem of a frictionless bead sliding down a parabola under gravity presents an interesting scenario for studying motion and dynamics. By using the principles of motion and Newton's laws, we can determine the position of the bead at any given time and analyze its motion in detail. Further exploration and calculations can be done to understand the behavior of the bead and its motion along the parabolic path.
 

1. What is a "frictionless bead sliding down a parabola"?

A frictionless bead sliding down a parabola is a theoretical concept used in physics to model the motion of a particle with no frictional forces acting on it as it moves along a curved path in the shape of a parabola.

2. How is this concept relevant to real-world situations?

While frictionless bead sliding down a parabola may not occur in the real world, it can be used to model and understand the behavior of objects in situations where friction is negligible, such as in space or in highly controlled laboratory experiments.

3. What are the key factors that affect the motion of a frictionless bead sliding down a parabola?

The key factors that affect the motion of a frictionless bead sliding down a parabola include the initial position and velocity of the bead, the shape of the parabola, and the acceleration due to gravity.

4. How does the position of the bead change as it slides down the parabola?

The position of the bead changes continuously as it slides down the parabola, following the shape of the curve. The bead will move faster as it gets closer to the bottom of the parabola, and will slow down as it reaches the top.

5. What are some real-world applications of this concept?

One example of a real-world application of this concept is in the design of roller coasters. By understanding the motion of a frictionless bead sliding down a parabola, engineers can design roller coasters with smooth and thrilling curves that provide an enjoyable ride for passengers.

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