- #1
sedaw
- 62
- 0
need to prove that if [tex]0\leq X<n[/tex]
and also 0<n so x=0.
The attempt at a solution
assume that x>0
[tex]\exists n, x\ni(0,\infty) |n< x [/tex]
contradiction !
for X<0 there's contradiction agin .
from here X have to be 0
is that right ?
and also 0<n so x=0.
The attempt at a solution
assume that x>0
[tex]\exists n, x\ni(0,\infty) |n< x [/tex]
contradiction !
for X<0 there's contradiction agin .
from here X have to be 0
is that right ?