Fluid mechanics question on forces on a cone in a pressurized tank

[iza888]

A plug in the bottom of the pressurized tank is conical in shape. The air pressure is 40kPa and the tank has a specific weight of 27kN/m^3. Determine the magnitude, direction, and line of action of the force exerted on the curved surface of the cone within the take due to the 40kpa pressure and liquid.




2. I don't know what to do :( :(



3. Ok so I have worked out the volume of the cone only dipped in solution - this gave me 0.349m^3

I know that Fc = Fair + W

I am getting confused with what area I have to find and how i know the area of the tank to work out the force... This question is driving me crazy could somebody please explain the steps they took so I can understand the logic. I have the solutions it is the logic of the answer that I do not understand.

 

[Valkarie]

Thank you in advance.The force on the curved surface of the cone is determined by the pressure and the weight of the liquid it is submerged in. To do this, you need to calculate the area of the curved surface of the cone, the pressure of the air, and the weight of the liquid. The area of the curved surface of the cone can be calculated using the formula A = πr^2, where r is the radius of the cone. The pressure of the air can be calculated from the given information, which is 40kPa. The weight of the liquid can be calculated from the specific weight of the liquid and the volume of the cone, which is 0.349m^3. The weight of the liquid is equal to the specific weight multiplied by the volume. Once these calculations are complete, the force exerted on the curved surface of the cone can be determined using the equation Fc = Fair + W, where Fc is the force on the curved surface, Fair is the pressure of the air, and W is the weight of the liquid. The magnitude of the force, its direction, and its line of action can then be determined.