Where is the Geometry Defined in the EBT and Timoshenko PDE's

In summary, the EBT and Timoshenko BT PDE's are formulated from first principles, and curved beams can be approximated as a set of short straight beams joined end to end.
  • #1
bugatti79
794
1
Folks,

To date I have been reading about Euler Bernoulli Beam and Timoshenko Beam Theory desribed by the following equations respectively

EBT ##\displaystyle \frac{d^2}{dx^2}\left( EI \frac{d^2 w}{dx^2}\right )+c_fw=q(x)##

Timoshenko ##\displaystyle -\frac{d}{dx} \left[GAK_s \left(\Psi+\frac{dw}{dx}\right)\right]+c_fw=q## and ##\displaystyle - \frac{d}{dx} \left(EI \frac{d \Psi}{dx}\right)+GAK_s \left(\Psi+\frac{dw}{dx}\right)=0##

These expressions seem to be for straight beams. Where in the above PDE's is the geometry of the beam defined?

For example, if one wants to analyse a quadrant of a ring say (from ##\pi/2## to ##\pi##) where it is constrained at ##\pi## position and a point load applied at ##\pi/2## position...

How is the PDE formulated?
 
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  • #2
bugatti79 said:
These expressions seem to be for straight beams.
Correct.

Where in the above PDE's is the geometry of the beam defined?
The basic assumptions about the deflected shape of the beam, and the relation between the strains and the geometry when it deflects, all assume the beam was straight.

For a curved beam, you have to go back to first principles and reformulate the equations of motion. In general this is complicated, because (unlike straight beams) the axial, torsional, and bending of the beam are all coupled together by the curvature. Googling "curved beam equations of motion" gives lots of hits.

As a simple example of why it gets complcated, the "neutral axis" of a curved beam is not at is geometrical mid point, because that assumption would mean there was more material on the "outside" of the curve than on the "inside". But if the position of the neutral axis depends on the radius of curvature, you have to make some approximations if the curvature suddenly changes (e.g. two straight sections of beam are joined by a circular arc.)

In practice, you can often approximate a curved beam as an set of short straight beams joined end to end, to get a numerical solution (e.g. from a finite element model).
 
  • #3
As a simple example of why it gets complcated, the "neutral axis" of a curved beam is not at is geometrical mid point,

Just to clarify this means that:

The neutral surface does not, in general, coincide with the centroid of a section as it does with a straight beam.
Even with the usual assumption that plane sections remain plane after straining the stress strain relationship is non-linear (non hookean) as it is with a straight beam where the stress is assumed proportional to the distance from the neutral surface.
 
  • #4
AlephZero said:
Correct.


The basic assumptions about the deflected shape of the beam, and the relation between the strains and the geometry when it deflects, all assume the beam was straight.

For a curved beam, you have to go back to first principles and reformulate the equations of motion. In general this is complicated, because (unlike straight beams) the axial, torsional, and bending of the beam are all coupled together by the curvature. Googling "curved beam equations of motion" gives lots of hits.

As a simple example of why it gets complcated, the "neutral axis" of a curved beam is not at is geometrical mid point, because that assumption would mean there was more material on the "outside" of the curve than on the "inside". But if the position of the neutral axis depends on the radius of curvature, you have to make some approximations if the curvature suddenly changes (e.g. two straight sections of beam are joined by a circular arc.)

In practice, you can often approximate a curved beam as an set of short straight beams joined end to end, to get a numerical solution (e.g. from a finite element model).

Studiot said:
Just to clarify this means that:

The neutral surface does not, in general, coincide with the centroid of a section as it does with a straight beam.
Even with the usual assumption that plane sections remain plane after straining the stress strain relationship is non-linear (non hookean) as it is with a straight beam where the stress is assumed proportional to the distance from the neutral surface.

Thanks Guys

Can you recommend some books or online sources on how

1) the EBT and Timoshenko BT PDE's are formulated from first principles?
2) Good Introductory books on the principle of virtual work (minimum potential energy)

I would like to study the deformation of rings under load using theoretical/FE methods, so any recommendations to this end would be appreciated... Thanks
 
  • #5




The geometry of the beam is defined in the boundary conditions of the PDEs. In the EBT, the geometry is defined by the boundary conditions of the beam's deflection and its second derivative at the ends of the beam. These boundary conditions determine the shape and curvature of the beam. Similarly, in the Timoshenko PDEs, the geometry is defined by the boundary conditions of the beam's deflection, its slope, and its second derivative at the ends of the beam. These boundary conditions also determine the shape and curvature of the beam.

To formulate the PDE for a quadrant of a ring, the geometry of the beam would need to be taken into consideration when defining the boundary conditions. This could involve constraints at specific points and the application of loads at certain positions, as mentioned in the example. The PDE would then need to be solved using these specific boundary conditions to analyze the behavior of the beam in that particular geometry.
 

1. Where does the geometry come into play in the EBT and Timoshenko PDE's?

The geometry is defined in the EBT and Timoshenko PDE's through the shape and dimensions of the structures being analyzed. These equations take into consideration the geometry of the material and the boundary conditions of the system.

2. How does the geometry affect the solutions of the EBT and Timoshenko PDE's?

The geometry has a significant impact on the solutions of the EBT and Timoshenko PDE's. The shape, size, and orientation of the structure being analyzed can change the boundary conditions and therefore alter the solutions of the equations.

3. Why is geometry an important factor in these PDE's?

Geometry is a crucial factor in these PDE's because it is a fundamental aspect of any structural analysis. The geometry determines the behavior of the structure under different loading conditions, and therefore, it is essential to consider it in these equations.

4. How do the EBT and Timoshenko PDE's handle different types of geometry?

The EBT and Timoshenko PDE's are versatile and can handle various types of geometry. These equations have been developed to handle both simple and complex geometries, including circular, rectangular, and irregular shapes.

5. Can the geometry be changed in the EBT and Timoshenko PDE's to analyze different structures?

Yes, the geometry can be altered in the EBT and Timoshenko PDE's to analyze different structures. These equations allow for the incorporation of different geometries, material properties, and boundary conditions, making them applicable to a wide range of structural analysis problems.

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