how do you "indicate transient terms" when y just equals 1 ?

Jeff12341234

t is the dependent variable in this problem and I'm told to "indicate transient terms". Well, t=1 so is this a trick question or did I do something wrong?

HallsofIvy

You seem to have forgotten the "constant of integration". t= 1 is one function satisfying this equation. There are others, involving terms that go to 0 as t goes to infinity.

Jeff12341234

ok, so t = 1 + c
or t = 1 + c/μ ?
Because the c term should've actually been introduced on the 2nd to last line. If that's true, that e^((e^x^2)/2) function should've also been divided by c when solving for t.