Triplet Paradox

greswd

Will the solution involve another trapezoid?

ghwellsjr

The non-IRF diagram using the radar method for each of the outside triplets calculating the path of the inside triplet will produce the same trapezoid as in the Twin Paradox "solution" but the shape they each calculate for the other outside triplet will be a more complicated.

But before we get to the complicated non-IRF diagram, I think you need to resolve your confusion over the simple IRF solutions. Can you provide specifics on what you are confused about?

greswd

I understand your previous trapezoid diagram well.

Will the shape both calculate for the other outside triplet be a trapezoid as well?

ghwellsjr

Then you should have no problem calculating the non-inertial rest frame for one of the outside triplets using the radar method. I have changed the scenario slightly to make it easier for you to do this. The only difference is that the traveling triplets go out for 16 months and 16 months coming back instead of just 12 each way, and the inertial triplet ages by 40 months:



No. Work it out and you'll see what it is.

Attached Thumbnails

 

greswd

Dayum, I gotta do this manually.

Why provide the LabVIEW graphing software only after we're done?

ghwellsjr

It's not that hard. Start by making a table like I did in post #92 and #93 (page 6).
Yes, otherwise, you won't appreciate it. But my software doesn't do non-inertial frames. It allows you to define a triplet scenario (speed and length of time for the traveling triplets) and draws the diagram in the inertial triplet's rest frame and then it uses the Lorentz Transformation to redraw it at whatever speed you want the new IRF to be moving relative to the original IRF.

When I did the non-inertial rest frames, it was all done by cut-and-paste in Paint and I have only done this one on graph paper.

greswd

I will appreciate it