probability of finding electrons in nucleus (s orbitals)by Enigman Tags: atomic structure, dualnature, electrons 

#1
Sep413, 06:04 AM

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Why is the probability of finding an electron of s orbital in the nucleus highest? Is Quantum Tunneling involved? If so, won't the electron need a large amount of energy to pass through the nucleus?




#2
Sep413, 07:53 AM

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Neither the electron nor the nucleus are billard balls, they don't "collide" as classical objects would do. The electron does not need any energy to be (partially) in the nucleus, and it does not "pass" the nucleus. 



#3
Sep413, 08:54 AM

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Why is the amplitude of wave function reach an antinode at the nucleus, making the probability density highest at the nucleus? Does it have anything to do with angular momentum being zero? The probability density graphs of s orbitals show a highest density at the center of nucleus so wouldn't an electron have to be fully in the nucleus? (Thats probably why I got the weird idea of tunneling; mixed it up with penetration. ) Or is it just a schrodinger's cat scenario? Can an electron be 'detected' experimentally at the nucleus? (ie.Collapsing the wave form and fixing position at nucleus) Also a reference book suggestion would be great the coursebook (Atkins elements of phys. chem.) is rather vague about most of the part, I'm self studying by Shankar's book on Q.M. but it doesn't deal with atomic structure (as far as I've read). Thanks in advance. 



#4
Sep413, 09:26 AM

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probability of finding electrons in nucleus (s orbitals)Books: no idea. 



#5
Sep413, 06:17 PM

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If you look at this site you can find some answers to your questions.
http://www.chemistry.mcmaster.ca/esa...section_2.html The electron in an atom is in a quantum state designated by n, l, m(l) and m(s). For all s orbitals we have l=0, and m(l) =0, so subsequentially the angular momentum and magnetic moment are zero. Orbital wave function can be broken up into a spherical polar coordinate part and a radial part. What you are referring to is the probability of finding the electron at a certain radial distance from the nucleus. There is another probability called the radial probability distribution, which is the radial probability of the wave function squared multiplied by the volume of a spherical shell of thickness dr at a distance r from the nucleuos. The maximum probability is given as where the electron is most likely to be found. ( Can be considered the size of the orbital ) For determining the whereabouts of the electron, the site states: How the wave function for an electron is determined I cannot say but it has to do with Schroedinger, de Broglie, particle in a box, and all that stuff. I kinda remember this stuff from old chemistry days and it is now somewhat vague. 



#6
Sep413, 08:39 PM

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Thanks for the replies mfb, 256bits.
They cleared a lot of doubts, incidentally I found a cool article about directly observing a wave function of hydrogen: http://physicsworld.com/cws/article/...hydrogenatom Also an another older article from nature for nitrogen molecule: http://www.nature.com/news/2004/0412...s0412137.html 


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