derivation of THp


by mhzq007
Tags: derivation, horsepower, power
mhzq007
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#1
Jan21-14, 02:55 AM
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hi everyone can anyone please give me a clue of how to derive this equation

Hp= Q(gpm)* Δp(psi)/1714

Q is volumetric flow rate
Δp is pressure
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Jan21-14, 04:09 AM
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Quote Quote by mhzq007 View Post
hi everyone can anyone please give me a clue of how to derive this equation

Hp= Q(gpm)* Δp(psi)/1714

Q is volumetric flow rate
Δp is pressure
1 HP = 33000 ft-lb/min.

1 gal. water = 8.33 lbs

for water, Δp = H * 144 in[itex]^{2}[/itex]/ft[itex]^{2}[/itex] / 62.4 lbs / ft,
where H is the pump head in feet of water

So

HP = Q*H / 33000 = [Q gal/min * 8.33 lbs / gal * H feet of water * Δp * (144/62.4 lbs / ft[itex]^{2}[/itex])] / 33000

HP = [Q * Δp * 8.33 * (62.4/144)] / 33000 = Q * Δp / 1714


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