- #1
Oxymoron
- 870
- 0
If I have a differential manifold, then I get the exterior derivative for free, that is, I don't have to impose any additional structure to my manifold.
However, this derivative is defined as an operator on forms. What makes the forms so special? Why doesn't a diff. manifold come with a derivative on covariant vectors? Or does it and I don't know about it?
However, this derivative is defined as an operator on forms. What makes the forms so special? Why doesn't a diff. manifold come with a derivative on covariant vectors? Or does it and I don't know about it?