- #1
Matt.D
- 25
- 0
Is the correct equation that relates to the electrical resistivity of a conducting material to its resistance:
p = RS/l
p = is the electrical resistivity
R = is the resistance of the material
S = is the cross-sectional area
l = is the length of the specimen
if I'm using the right formula, would my answer to this question be correct?
A potential difference of 1.5V exists across the ends of a copper wire of length 2.0m and uniform radius 0.40mm. Calculate the current in the wire.
I've been given the resistivity of copper as 1.7 x 10^-4 ohms.meter
[Answer]
p = RS/l
= (1.7 x 10^-4) x 0.40mm / 2.0m
= 0.0007 x 0.0004 / 2.0
= 0.00000014
corecto?
p = RS/l
p = is the electrical resistivity
R = is the resistance of the material
S = is the cross-sectional area
l = is the length of the specimen
if I'm using the right formula, would my answer to this question be correct?
A potential difference of 1.5V exists across the ends of a copper wire of length 2.0m and uniform radius 0.40mm. Calculate the current in the wire.
I've been given the resistivity of copper as 1.7 x 10^-4 ohms.meter
[Answer]
p = RS/l
= (1.7 x 10^-4) x 0.40mm / 2.0m
= 0.0007 x 0.0004 / 2.0
= 0.00000014
corecto?