- #1
madeinmsia
- 15
- 0
Homework Statement
50uA beam of 1MeV proton
Target = Iron of 0.05um thick
Calculate scattered current density at distance 5 cm at 20 degrees angle
Homework Equations
[tex]\sigma(E,\theta)[/tex] = [tex]\pi*Z_{1}Z_{2}e^{4}(M_{1}/M_{2})/ET^{2}[/tex]
The Attempt at a Solution
I figured the probability of scattering to the angle is [tex]\frac{\int^{20}_{20}\sigma(E,\theta)d\Omega}{\int^{\pi}_{0}\sigma(E,\theta)d\Omega}[/tex]
Then how do i find the scattered current density with the info I have?