- #1
csc2iffy
- 76
- 0
Maximize Z = 4x + 5y + 3z
subject to
x + y + 2z ≥ 20
15x + 6y + 5z ≤ 50
x + 3y + 5z ≤ 30
and x ≥ 0, y ≥ 0, z ≥ 0
Work through the simplex method step by step to demonstrate that this problem does not possesses any feasible solutions
subject to
x + y + 2z ≥ 20
15x + 6y + 5z ≤ 50
x + 3y + 5z ≤ 30
and x ≥ 0, y ≥ 0, z ≥ 0
Work through the simplex method step by step to demonstrate that this problem does not possesses any feasible solutions