Plasma in magnetic field in equilibrium

Overall, your approach is a good starting point for solving for the magnetic field in terms of a known pressure in a plasma in a magnetic field.
  • #1
vibe3
46
1
Hello,

Starting from the equilibrum equation of a steady-state plasma in a magnetic field:
[tex]
(1) \nabla P = \vec{J} \times \vec{B}
[/tex]
where [itex]P = nkT[/itex] is the plasma pressure, [itex]\vec{J}[/itex] is the current and [itex]\vec{B}[/itex] is the magnetic field, I am trying to solve for the magnetic field [itex]\vec{B}[/itex] in terms of a known pressure [itex]P[/itex].

Using [itex]\vec{J} = \frac{1}{\mu_0} \nabla \times \vec{B}[/itex], and the identity [itex]\vec{B} \times (\nabla \times \vec{B}) + (\vec{B} \cdot \nabla) \vec{B} = \nabla( B^2/2)[/itex], the first equation becomes
[tex]
(2) \nabla \left( P + \frac{B^2}{2 \mu_0} \right) = \frac{1}{\mu_0} (\vec{B} \cdot \nabla) \vec{B}
[/tex]
Dotting both sides by a path length [itex]\vec{ds}[/itex] and integrating from the point of interest [itex]\vec{r}[/itex] to some other point [itex]p_2[/itex], and then using the gradient theorem gives
[tex]
(3) P(p_2) + \frac{B^2(p_2)}{2 \mu_0} - P(\vec{r}) - \frac{B^2(\vec{r})}{2 \mu_0} = \frac{1}{\mu_0} \int_{\vec{r}}^{p_2} \left[ (\vec{B} \cdot \nabla) \vec{B} \right] \cdot \vec{ds}
[/tex]
The integrand of (3) can be expressed as
[tex]
(4) \frac{1}{\mu_0} (\vec{B} \cdot \nabla) \vec{B} = \hat{b} \frac{\partial}{\partial l} \left( \frac{B^2}{2 \mu_0} \right) - \hat{n} \frac{B^2}{\mu_0 R_c}
[/tex]
where [itex]l[/itex] is a coordinate along a magnetic field line, [itex]\hat{b}[/itex] is a unit vector tangent to the field line, [itex]\hat{n}[/itex] is a unit vector normal to the field line and anti-radial, and [itex]R_c[/itex] is the radius of curvature of the field line (see for example Plasma physics and controlled nuclear fusion By Kenrō Miyamoto, eq 6.7).

By choosing the path of integration either in the [itex]\hat{b}[/itex] direction or [itex]\hat{n}[/itex] direction perhaps we can get a solution.

CHOICE 1: [itex]\vec{ds} = \hat{n} ds[/itex]

Here, we will choose [itex]p_2[/itex] to be infinity, where we have the advantage that all quantities will go to 0. So (3) becomes
[tex]
(5) P(\vec{r}) + \frac{B^2(\vec{r})}{2 \mu_0} = \frac{1}{\mu_0} \int_{\vec{r}}^{\infty} \frac{B^2}{R_c} ds
[/tex]
Unfortunately, it does not seem that there is a closed form solution to this integral.

CHOICE 2: [itex]\vec{ds} = \hat{b} dl[/itex]

Here, we are integrating along a field line, but there does not seem to be an obvious choice for [itex]p_2[/itex], but the integral will be trivial. Leaving [itex]p_2[/itex] in place for now, we find that (3) becomes
[tex]
(6) P(p_2) + \frac{B^2(p_2)}{2 \mu_0} - P(\vec{r}) - \frac{B^2(\vec{r})}{2 \mu_0} = \frac{B^2(p_2)}{2 \mu_0} - \frac{B^2(\vec{r})}{2 \mu_0}
[/tex]
which unfortunately leads to [itex]P(\vec{r}) = P(p_2)[/itex] which isn't very helpful. Interestingly, if we integrate the other way on the field line, so that [itex]\vec{ds} = -\hat{b} dl[/itex] we get a completely different solution:
[tex]
(7) B^2(\vec{r}) = B^2(p_2) - \mu_0 (P(\vec{r}) - P(p_2))
[/tex]
which has the unfortunate property that the solution depends on which point [itex]p_2[/itex] we pick. Can anyone shed some light on where I'm going wrong with these integrals? Many thanks
 
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  • #2
Hello,

Thank you for sharing your work on solving for the magnetic field in terms of a known pressure in a steady-state plasma. Your approach using the equilibrium equation and identities for the current and magnetic field is a good starting point. However, there are a few things that I believe may be causing issues in your integrals.

Firstly, in your second choice for \vec{ds} = \hat{b} dl, the integral should not be trivial. The path of integration should be from \vec{r} to p_2, with p_2 being any point along the field line. This means that the integral should still have a dependence on p_2, and the solution should not reduce to P(\vec{r}) = P(p_2).

Secondly, in both of your choices for \vec{ds}, there seems to be a mistake in the integrand. The term \frac{B^2}{R_c} should not be multiplied by \hat{n} or \hat{b}, as it is a scalar quantity. This may be causing issues with your integrals and leading to incorrect solutions.

Lastly, it is important to note that the equilibrium equation you are using assumes that the plasma is in a steady-state, meaning that the plasma pressure and current are constant in time. If this assumption is not met, then the equilibrium equation may not be applicable and could lead to incorrect solutions.

I hope this helps to shed some light on where the issue may be in your integrals. Keep up the good work and don't hesitate to reach out if you have any further questions.
 

1. What is plasma in a magnetic field in equilibrium?

Plasma in a magnetic field in equilibrium refers to the state where charged particles in a plasma are evenly distributed and move in a stable manner within a magnetic field.

2. How is equilibrium achieved in a plasma in a magnetic field?

Equilibrium in a plasma in a magnetic field is achieved when the magnetic and electric forces acting on the charged particles are balanced, resulting in a stable state.

3. What is the significance of studying plasma in a magnetic field in equilibrium?

Understanding the behavior of plasma in a magnetic field in equilibrium is important in many areas of science and technology, including fusion energy research, space physics, and plasma processing.

4. How does the strength of the magnetic field affect a plasma in equilibrium?

The strength of the magnetic field plays a crucial role in determining the behavior of a plasma in equilibrium. A stronger magnetic field can confine the charged particles more effectively, resulting in a more stable equilibrium state.

5. Can a plasma in a magnetic field ever be completely in equilibrium?

No, a plasma in a magnetic field can never be completely in equilibrium due to the constant movement of the charged particles. However, it can reach a state of quasi-equilibrium where the fluctuations are small and the system appears to be in a stable state.

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