- #1
Iclaudius
- 36
- 0
Howdy ya'll,
a relatively simple question,
A circular bar 20mm in diameter and 1m long is subjected to an axial load of 50kN. Determine:
(i) The normal stress.
(ii) The normal strain.
(iii) The elongation.
Assume the material is steel with an Elastic Modulus of 200GPa.
ok so i got normal stress = 159 MPa, normal strain = 795*10^-6,
but here is my problem - solving for elongation why can i not just plug in the strain amount and solve for the change in length i.e strain * original length = change in length?
by the way elongation = 0.8mm which is not what i get using the aforementioned method.
(sorry for no math symbols)
Thanks in advance,
Claudius
a relatively simple question,
A circular bar 20mm in diameter and 1m long is subjected to an axial load of 50kN. Determine:
(i) The normal stress.
(ii) The normal strain.
(iii) The elongation.
Assume the material is steel with an Elastic Modulus of 200GPa.
ok so i got normal stress = 159 MPa, normal strain = 795*10^-6,
but here is my problem - solving for elongation why can i not just plug in the strain amount and solve for the change in length i.e strain * original length = change in length?
by the way elongation = 0.8mm which is not what i get using the aforementioned method.
(sorry for no math symbols)
Thanks in advance,
Claudius