Length error which is 2+-1

In summary: So xy would be 6+- 0.07*2= 5.3302. In summary, Hypercase said that if you have length errors which are 2+-1, add the absolute errors. If you have division or multiplication errors, add the percentage errors. If you have cubes and squares etc. multiply the percentage error by the power. Finally, if you want to be very precise, you could do this: Subtract the absolute errors from the percentage errors.
  • #1
Pixter
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0
Right having a few labs at the moment and just wanted to get a clarificating conserning errors.

if i have a length error which is 2+-1... if i add two length or subtract two length, what do i do with the error?
the same if i multiply them och divide them...

and then finally if i sqaure,kube or take the sqrt of them..?

it's not that important could probably ask a tutor but have not lectures today so don't have to get the bus to the uni then =).
 
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  • #2
for addition and subtraction add the absolute errors.
For division and multiplication add the percentage errors.
for cubes and squares etc. multiply the percentage error by the power.
 
  • #3
Hypercase gave very good "rules of thumb". They are not exactly right but very, very accurate for small errors (surely you can do better than "2+-1"!) and far easier than being precise.

If you really want to be precise (of course, your "errors" won't be very precise anyway!) you could do this:
Suppose x is measured at 2+- 0.01, y is measured at 3+- 0.02.
That means that the true value of x is somewhere between 2-0.01= 1.99 and 2+0.01= 2.01. The true value of y is somewhere between 3- 0.02= 2.98 and 3+0.02= 3.02. The largest possible value for x+ y is 2.01+ 3.02= 5.03.
The smallest possible value of x+y is 1.99+ 2.98= 4.97. x+y is somewhere between 4.97 and 5.03: 5+- 0.03. Exactly what Hypercase said: the errors added.
Notice, by the way, that if you subtract the errors do not subtract! They still add. The largest x- y could possibly be is 2.01- 2.98= -0.97, the smallest is 1.99- 3.02= -1.03: x-y is -1+- 0.03- the error is still the sum of the errors.

Now what about xy? The largest xy could be is 2.01*3.02= 6.0702= 6+ 0.0702. The smallest is 1.99*2.98= 5.9302= 6-0.0698. A bit more complicated! To use Hypercases's suggestion, find the percentage error (also called "relative error") in x: 0.01/2 and in y: 0.02/3.
Adding those, the percntage error in xy is 0.03/6+ 0.04/6= 0.07/6 and the absolute error is 6(0.07/6)= 0.07: xy is 6+- 0.07 which, while not exact, is pretty darn accurate.
As Hypercase said, since powers are "repeated multiplication" you do a "repeated addition", i.e. multiplication, of the percentage error.
 

1. What is length error?

Length error refers to the difference between the actual length or measurement of an object and the intended or expected length. It can be positive or negative, depending on whether the measurement is longer or shorter than the intended length.

2. What does 2+-1 mean in terms of length error?

The notation 2+-1 indicates that the length error has a magnitude of 1 unit, with a possible range of 2 units to 1 unit. This means that the measurement could be either 1 unit shorter or 2 units longer than the intended length.

3. How is length error calculated?

Length error is calculated by taking the difference between the measured length and the intended length, and then expressing it as a percentage or absolute value. For example, if an object is intended to be 10 cm long but is measured to be 9.5 cm, the length error would be calculated as (10-9.5)/10 = 5% or 0.5 cm.

4. What causes length error?

Length error can be caused by various factors such as human error in measurement, limitations of measuring tools, environmental factors (e.g. temperature, humidity), and physical properties of the object being measured (e.g. expansion or contraction due to heat). It is important to identify and minimize these factors in order to reduce length error.

5. How can length error be minimized?

To minimize length error, it is important to use precise and calibrated measuring tools, take multiple measurements and calculate an average, control environmental factors, and ensure proper technique in measurement. Using the appropriate units and understanding the concept of significant figures can also help in reducing length error.

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