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Uniform Circular Motion vs Circular Orbit due to Gravity

by Slvtmong00se
Tags: circular, gravity, motion, orbit, uniform
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Slvtmong00se
#1
Aug13-14, 09:32 AM
P: 10
In uniform circular motion, (eg, a mass on the end of a string moving in a horizontal circle) centripetal force is the only thing causing acceleration. we have the kinematic relationship V=RW
or velocity is proportional to radius. I.e a bigger radius means greater linear speed?

For the motion of a satellite in earth orbit in uniform circular motion, we have centripetal force due to gravity alone. Equating the force of gravity to centripetal force we obtain

V=square root of :(GM/R)

i.e. speed is now INVERSELY proportional to orbital radius.

I dont understand whats going on here. How can a centrally directed force, being the only thing causing acceleration, lead to two different relationships between V and R?
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sophiecentaur
#2
Aug13-14, 09:56 AM
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There are two different things at work here. A gravitational orbit can only have one radius for a given tangential speed -
when Gm1m2/r2 = v2/r.
A mass on a string can have any speed and the tension will vary accordingly. For a mass on a string of length r, the centripetal force will be the same as the g force in an orbit of radius r.
Nothing to worry about. You have two independent variables with string but just one with an orbit.
Slvtmong00se
#3
Aug13-14, 10:28 AM
P: 10
But isnt tension constant in a horizontal circle? I dont get what the two variables are in the mass on a string case. I did the calculation you mention. Indeed, for a length of string equal to R we get the same results for velocity.

Also, for a given angular velocity (and hence period), V=RW describes both cases. But if you double R, in one case the speed increases and in the other it decreases. Which is my original problem.

Put another way, if things in smaller radii orbit move faster in gravity, why do points on the earths equator move faster than those further in? I know its a pretend rigid body, but the force is gravitation in both cases, no?

Sorry, Im still confused.

Nathanael
#4
Aug13-14, 11:30 AM
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Uniform Circular Motion vs Circular Orbit due to Gravity

Quote Quote by Slvtmong00se View Post
I dont get what the two variables are in the mass on a string case.
In an orbit, the centripetal force is determined by the radius. With a string, the centripetal force can vary.

Quote Quote by Slvtmong00se View Post
Also, for a given angular velocity (and hence period), V=RW describes both cases. But if you double R, in one case the speed increases and in the other it decreases. Which is my original problem.
Doubling R only increases the velocity if you consider the angular velocity constant. Do you think it is reasonable to assume that the angular velocity is constant regardless of the radius of orbit?

Quote Quote by Slvtmong00se View Post
Put another way, if things in smaller radii orbit move faster in gravity, why do points on the earths equator move faster than those further in? I know its a pretend rigid body, but the force is gravitation in both cases, no?
In an orbit, you have to get the speed exactly right to match the gravitational(/centripetal) force. The smaller the orbital radius, the faster you need to be moving.

On Earth however, if the gravitational force is too large for our "orbit" then we will still "orbit" because there is the normal force which balances the excess gravitational force.

So we don't need to be moving at the speed that your orbital-equations would say, because we are no longer required to move at such a speed that ALL of the gravitational force causes centripetal acceleration.
(Maybe I could've said it better, but I hope it makes sense?)
Slvtmong00se
#5
Aug13-14, 11:43 AM
P: 10
Thanks guys, but I keep thinking I get it and then I end up getting stuck again.

In an orbit, the centripetal force is determined by the radius. With a string, the centripetal force can vary.
In a horizontal circle, isnt string tension constant? Why would it change?

Doubling R only increases the velocity if you consider the angular velocity constant. Do you think it is reasonable to assume that the angular velocity is constant regardless of the radius of orbit?
So if we consider two geosynchronus satellites, one R out and another 2R out from the center of the earth, which will have greater speed?

In an orbit, you have to get the speed exactly right to match the gravitational(/centripetal) force. The smaller the orbital radius, the faster you need to be moving.

On Earth however, if the gravitational force is too large for our "orbit" then we will still "orbit" because there is the normal force which balances the excess gravitational force.

So we don't need to be moving at the speed that your orbital-equations would say, because we are no longer required to move at such a speed that ALL of the gravitational force causes centripetal acceleration.
Maybe Im missing something here, but this doesnt explain to me why points on the equator move *faster* than those elsewhere on the surface of the earth.
rcgldr
#6
Aug13-14, 11:45 AM
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Quote Quote by Slvtmong00se View Post
For the motion of a satellite in earth orbit in uniform circular motion, we have centripetal force due to gravity alone. Equating the force of gravity to centripetal force we obtain

V=square root of :(GM/R)

i.e. speed is now INVERSELY proportional to orbital radius.
for a satellite in orbit you also have

W=square root of :(GM/R^3)
Nathanael
#7
Aug13-14, 11:59 AM
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Quote Quote by Slvtmong00se View Post
In a horizontal circle, isnt string tension constant? Why would it change?
It is constant for a given constant angular velocity and constant radius, but the point is that the tension is "free to change"

In other words, if I increased the angular velocity, the tension would increase appropriately.

However for orbits, if you increase the angular velocity, then the gravity does not increase (and so you lose your orbit)

Quote Quote by Slvtmong00se View Post
So if we consider two geosynchronus satellites, one R out and another 2R out from the center of the earth, which will have greater speed?.
The thing is, you can't have two geosynchronous satellites at different radii. There is only one radius (for Earth) that results in a geosynchronous orbit.


Quote Quote by Slvtmong00se View Post
Maybe Im missing something here, but this doesnt explain to me why points on the equator move *faster* than those elsewhere on the surface of the earth.
No you're right, I didn't explain that part. It's because in this situation, the angular velocity is held constant, and so increasing the radius (which is maximum at the equater) increases the speed. (V=ωR)
Drakkith
#8
Aug13-14, 01:25 PM
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Quote Quote by Slvtmong00se View Post
In a horizontal circle, isnt string tension constant? Why would it change?
You can change the velocity of the circling object, which would increase or decrease the string tension, without changing the radius. You cannot do this with an orbiting object.


So if we consider two geosynchronus satellites, one R out and another 2R out from the center of the earth, which will have greater speed?
You cannot have geosynchronous satellites at different distances from the Earth. In order to stay in a circular geosynchronous orbit the satellites must orbit at the same distance from the Earth. However, this does not preclude having elliptical geosynchronous orbits. In this case, the satellite would speed up as it approached the Earth and slow down as it receded. However, the average speed would remain the same no matter the shape of the orbit.

Note that geostationary orbits are different from geosynch orbits. Geostationary orbits are where the satellite remains in the same spot in the sky relative to an observer on Earth. Geosynchronous orbits are orbits where the satellite's orbital period is equal to one day, regardless of where in the sky it happens to drift. You can have satellites pass over the poles of the Earth in a geosynchronous orbit. The orbital requirements for a satellite to be in a geostationary orbit are even more strict than a geosynch. There is only one plane and one radius the satellite can orbit in and still stay above the same location on the Earth. Changing the radius, speed, or inclination of the satellite would put it in a non-geostationary orbit.
Slvtmong00se
#9
Aug14-14, 01:34 PM
P: 10
Yes, I do think I get it now. fundamentally, the general conclusion then is, if someone asks me what happens in uniform circular motion when the radius of the circle changes, the answer is it depends on the functional form of the force causing the motion, yes?
Nathanael
#10
Aug14-14, 02:03 PM
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Quote Quote by Slvtmong00se View Post
if someone asks me what happens in uniform circular motion when the radius of the circle changes, the answer is it depends on the functional form of the force causing the motion, yes?
I think you have the right idea. The radius (and speed) can only change in a way that is "allowed" by whatever is causing the centripetal force.

Some sources of centripetal force (such as gravity) are more limited to change than others (such as a rope's tension)


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