- #1
bobbarkernar
- 48
- 0
i have no idea on how to start this problem.
Find a solution of the initial-value problem
dy/dx= -y^2 , y(0)=.0625
so..
(1/-y^2)dy = dx
int(1/-y^2)dy=int(dx)
1/y=x+c
please if someone can help me start it or explain it to me
Find a solution of the initial-value problem
dy/dx= -y^2 , y(0)=.0625
so..
(1/-y^2)dy = dx
int(1/-y^2)dy=int(dx)
1/y=x+c
please if someone can help me start it or explain it to me