How Is the Formula for Radiation Pressure on a Reflecting Surface Derived?

  • Thread starter premed
  • Start date
  • Tags
    Formula
In summary, for a reflecting surface, the radiation pressure is equal to 2I/c where I is the intensity of light and c is the speed of light. This can be seen by considering the force exerted by the photons, which is equal to the total momentum transferred divided by time. For reflection, the photon bounces off and transfers twice its momentum, resulting in a radiation pressure of 2I/c. However, for absorption, the photon only transfers its own momentum, resulting in a radiation pressure of I/c. This concept is important in understanding the effects of light on surfaces and objects.
  • #1
premed
10
0
for a reflecting surface, the radiation pressure is equal to 2I/c where I is the intensity of light and c is the speed of light. I saw this in my physics homework manual but it was never mentioned in the book. thanks.
 
Physics news on Phys.org
  • #2
First, recall that the intensity I is the average of the poynting (sp?) vector, so it is the energy flux. I.e., it's the number of incoming photons times their energy divided by time and divided by area (that's what "flux" means "whatever" flux is "whatever" per unit time per unit area)... that is
[tex]
I=\frac{\hbar\omega N}{\rm time*Area}
[/tex]
where N is the number of photons and \hbar\omega is the energy of a single photon.

So

[tex]
{\rm Pressure}=\frac{\rm Force}{\rm Area}
[/tex]
and the Force is the total momentum transferred divided by the time. For reflection the photon bounces off so that it transfers an amount of momentum [itex]\Delta p=2p[/itex],
so the total force due to N reflecting photons is (2pN)/(time)
[tex]
{\rm Pressure}=\frac{2pN}{\rm time*Area}=\frac{2\hbar\omega N}{c{\rm * time*Area}}
=\frac{2I}{c}
[/tex]

wheras, for absorption the momentum imparted by a single photon is [itex]\Delta p=p[/itex], which gives
[tex]
P=\frac{I}{c}
[/tex]
 
  • #3


The formula for radiation pressure on a reflecting surface is derived from the principles of electromagnetism and the behavior of light. When light strikes a surface, it exerts a force known as radiation pressure. This force is caused by the transfer of momentum from the photons of light to the surface.

The intensity of light, represented by the variable I, is a measure of the amount of energy carried by the light per unit area. This means that the higher the intensity of light, the more photons are present and the greater the force of radiation pressure.

The speed of light, represented by the variable c, is a fundamental constant in physics that describes the speed at which light travels in a vacuum. This constant is used to convert the energy of light (measured in watts) to a force (measured in newtons).

In order to derive the formula for radiation pressure, we use the equation for momentum, which states that the momentum of an object is equal to its mass multiplied by its velocity. In this case, the object is a photon of light and its velocity is the speed of light.

By equating the momentum of a photon to the force of radiation pressure, we can derive the formula 2I/c. This means that for every unit of intensity, there is a corresponding force of 2/c acting on the reflecting surface.

It is important to note that this formula is only applicable to perfectly reflecting surfaces, as some energy will be absorbed or transmitted by other surfaces. Additionally, this formula assumes that the light is hitting the surface at a perpendicular angle.

In summary, the formula for radiation pressure on a reflecting surface is derived from the principles of electromagnetism and the behavior of light. It is a fundamental equation in physics that helps us understand the effects of light on surfaces.
 

1. How is this formula derived?

The process of deriving a formula involves using mathematical principles and logic to determine the relationship between different variables and constants. This typically involves starting with a set of known equations or laws and manipulating them to find a new equation that describes the relationship between the variables in the formula.

2. What are the steps involved in deriving a formula?

The steps involved in deriving a formula may vary depending on the specific problem and variables involved, but generally involve identifying the known equations or laws, manipulating them using algebraic or calculus techniques, and verifying the result through experimentation or further analysis.

3. Why is it important to understand how a formula is derived?

Understanding how a formula is derived allows for a deeper understanding of the underlying principles and relationships involved. This can help in applying the formula to different scenarios and in recognizing when the formula may not be applicable.

4. Can a formula be derived in more than one way?

Yes, there may be multiple approaches or methods for deriving a formula. Some may be more straightforward or intuitive, while others may involve more complex mathematical techniques. The key is to find a method that leads to a correct and useful formula for the given problem.

5. Is it necessary to have a strong background in mathematics to derive a formula?

While a strong background in mathematics can certainly be helpful in deriving formulas, it is not always necessary. With a clear understanding of the problem and basic mathematical skills, it is possible to derive a formula through logical reasoning and basic algebraic or calculus techniques.

Similar threads

  • Astronomy and Astrophysics
Replies
20
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
2K
  • Classical Physics
Replies
22
Views
1K
Replies
9
Views
1K
  • Mechanics
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
909
Replies
6
Views
999
  • Introductory Physics Homework Help
Replies
3
Views
1K
Replies
12
Views
2K
  • Introductory Physics Homework Help
Replies
1
Views
937
Back
Top