Average Value of a Function notion

In summary, for polarized and isotropic radiation, the angle between the direction of polarization and the electric dipole vector is random. The average value of cos² θ over a spherical surface is 1/3, regardless of the direction of the polarization vector. This means that cos² θ can be replaced by its average value of 1/3 in calculations.
  • #1
Kreizhn
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Homework Statement


In a textbook that I'm reading, the authors have stipulated that for polarized and isotropic radiation, the angle between the direction of polarization and the electric dipole vector is random, and so we can replace [itex] cos^2 \theta [/itex] by its average 1/3.

I cannot see how this is possible. Can anyone shed some light on this? Am I using the wrong notion of "average"?

Homework Equations


The average value of a function f over an interval [a,b] is given by

[tex] \displaystyle \frac{1}{b-a} \int_a^b f(x) dx [/tex]

The Attempt at a Solution


I don't believe it is mathematically possible for the average value of cos² to reach 1/3, since if one does the integral, and calculates the absolute minimum value, they should find something along the lines of 0.39, which is greater than 1/3. Thus I must be missing something.
 
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  • #2
It's not talking about the average value over an interval, it's talking about the average value over a spherical surface. Specifically, if the direction of the dipole vector is selected randomly from the unit sphere and θ is the angle between it and the polarization vector, then cos² θ will be on average:

[tex]\frac{1}{4\pi} \int \cos^2 \theta\ \text{d}S[/tex]

Where the integral is taken over the unit sphere. Note that by symmetry, this integral will be the same regardless of what direction the polarization vector is pointing, so picking one and doing the surface integral reveals that this value is indeed 1/3.
 

1. What is the average value of a function?

The average value of a function is the value that represents the average height of the function over a given interval. It is calculated by taking the integral of the function over the interval and dividing it by the length of the interval.

2. How is the average value of a function calculated?

The average value of a function is calculated by taking the integral of the function over a given interval and dividing it by the length of the interval. The formula for average value is:

Average value = 1/(b-a) * ∫ab f(x)dx

3. What is the significance of the average value of a function?

The average value of a function is significant because it represents the average height of the function over a given interval. It can be used to find the average rate of change of the function, which can be useful in real-world applications such as finding average speed or average temperature over a period of time.

4. Can the average value of a function be negative?

Yes, the average value of a function can be negative. This means that the function has values below the x-axis over the given interval. The average value will be negative if the integral of the function over the interval is negative, indicating that the area under the curve is mostly below the x-axis.

5. How is the average value of a function related to the mean value theorem?

The average value of a function is related to the mean value theorem because it is essentially the same concept. The mean value theorem states that if a function is continuous on a closed interval, then there exists at least one point on the interval where the instantaneous rate of change (derivative) of the function is equal to the average rate of change (slope of the secant line). This point is also known as the average value of the function on the given interval.

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