- #1
aeonsky
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I need to find the derivative of the function below...
[itex]G(x) = \int_{x}^{1} cos(\sqrt{t}) dt[/itex]
FTC1
If f is continuous on [a,b], then the function g defined by
[itex]g(x) = \int_{a}^{x} f(t) dt[/itex] [itex]a \leq x \leq b[/itex]
is continuous on [a,b] and differentiable on (a,b) and [itex]g'(x) = f(x)[/itex]
Would it be [itex]-cos(sqrt(t))[/itex]
Thanks for the time!
Homework Statement
[itex]G(x) = \int_{x}^{1} cos(\sqrt{t}) dt[/itex]
Homework Equations
FTC1
If f is continuous on [a,b], then the function g defined by
[itex]g(x) = \int_{a}^{x} f(t) dt[/itex] [itex]a \leq x \leq b[/itex]
is continuous on [a,b] and differentiable on (a,b) and [itex]g'(x) = f(x)[/itex]
The Attempt at a Solution
Would it be [itex]-cos(sqrt(t))[/itex]
Thanks for the time!
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