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bfpri
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An aquarium 2 m long, 1 m wide, and 1 m deep is full of water. Find the work needed
to pump half the water out of the aquarium. (The density of water, p, is 1000 kg/m3,
and acceleration due to gravity, g, is 9.8 m/s2.)
So in order to truly understand how to do these kind of problems I decided to find different ways to solve this problem. Since you can integrate with respect to dx or dy, for dx i was wondering if you could integrate with respect to the 2m side like so
*edit..ugh its not letting me post the pictures so i'll just give the link...http://img19.imageshack.us/img19/2024/boxid.gif
In order to get the answer i integrated F*D. F=p*g*volume=pg(1); D=1-x
integral((1-x)(1)pgdx) from x=0 to x=1. But when i do, i get the wrong answer, 4900 J. The answer should be 2450 J =/
to pump half the water out of the aquarium. (The density of water, p, is 1000 kg/m3,
and acceleration due to gravity, g, is 9.8 m/s2.)
So in order to truly understand how to do these kind of problems I decided to find different ways to solve this problem. Since you can integrate with respect to dx or dy, for dx i was wondering if you could integrate with respect to the 2m side like so
*edit..ugh its not letting me post the pictures so i'll just give the link...http://img19.imageshack.us/img19/2024/boxid.gif
In order to get the answer i integrated F*D. F=p*g*volume=pg(1); D=1-x
integral((1-x)(1)pgdx) from x=0 to x=1. But when i do, i get the wrong answer, 4900 J. The answer should be 2450 J =/
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