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stripes
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Homework Statement
[tex]\int^{1}_{0}\frac{dx}{\sqrt{1-x^{2}}}[/tex]
Homework Equations
None
The Attempt at a Solution
[tex]\int^{1}_{0}\frac{dx}{\sqrt{1-x^{2}}} = sin^{-1}x\right|^{1}_{0}[/tex]
[tex]sin^{-1}x\right|^{1}_{0} = \frac{\pi}{2} - 0[/tex]
so the final answer is just pi/2. I have no problem computing the answer, but it's in the improper integrals section of the textbook...but I don't see this as being an improper integral. There's no need to deal with infinity at all, no asymptotes, no discontinuity on the closed interval [0,1].
Am I missing something?
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