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Finding the general expression of the nth term 
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#1
Jul612, 08:54 AM

P: 21

1. The problem statement, all variables and given/known data
Given successive terms of numbers starting from the 1st term: 11, 21, 35, 53, 75, 101,... What is the general expression of the nth term? where n is positive integer 2. Relevant equations / 3. The attempt at a solution Can't find a good attempt. 


#3
Jul612, 09:05 AM

HW Helper
P: 2,949




#4
Jul612, 09:15 AM

P: 21

Finding the general expression of the nth term
sorry I don't know...
how will you determine a general expression for it in this problem without trial and error? is it like finding a needle in the ocean? 


#5
Jul612, 10:07 AM

P: 2,939

look at the terms, then form a sequences of differences and what do you get?
10 , 14, 18, 22, 26 ... look at the differences as a sequence and what do you see? write an expression to generate the differences sequence term(n)= term(0) + 4*(n1) where n=1, 2, 3, 4... then write an expression to generate your sequence using the differences expression TERM(n) = TERM(0) + ... 


#6
Jul612, 10:32 AM

P: 9

Ouw... I think you can use the Sn to calculate the Un...



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