- #1
joseph12
- 1
- 0
I am trying to understand the origin of the following expression for the reaction field (dipole [tex]\mu[/tex] in spherical cavity surrounded by medium of permittivity [tex]\epsilon[/tex]):
[tex]
\begin{equation*}
R= \frac{2 \mu}{4\pi\epsilon_0\rho^3} f(\epsilon)
\end{equation}
[/tex]
where f(\epsilon) is _not_ the Kirkwood function,
[tex]
\begin{equation*}
f(\epsilon)=\frac{\epsilon-1}{2\epsilon+1},
\end{equation}
[/tex]
but the following:
[tex]
\begin{equation*}
f(\epsilon)=\frac{\epsilon-1}{2\epsilon+4}.
\end{equation}
[/tex]
I simply can not figure out the idea behind the third expression. I have already considered [tex]\epsilon_i\ne1[/tex] for the interior of the spherical cavity, or a polarizable dipole taking as refractive index squared, [tex]n^2[/tex]=2 or 4 arbitrarily. I got many similar expressions in this way but unfortunately not the desired one. Has somebody encountered this expression already and can shed some light on its origin?
Thanks,
Joseph
[tex]
\begin{equation*}
R= \frac{2 \mu}{4\pi\epsilon_0\rho^3} f(\epsilon)
\end{equation}
[/tex]
where f(\epsilon) is _not_ the Kirkwood function,
[tex]
\begin{equation*}
f(\epsilon)=\frac{\epsilon-1}{2\epsilon+1},
\end{equation}
[/tex]
but the following:
[tex]
\begin{equation*}
f(\epsilon)=\frac{\epsilon-1}{2\epsilon+4}.
\end{equation}
[/tex]
I simply can not figure out the idea behind the third expression. I have already considered [tex]\epsilon_i\ne1[/tex] for the interior of the spherical cavity, or a polarizable dipole taking as refractive index squared, [tex]n^2[/tex]=2 or 4 arbitrarily. I got many similar expressions in this way but unfortunately not the desired one. Has somebody encountered this expression already and can shed some light on its origin?
Thanks,
Joseph