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Validity of netwon's laws on the earth's surface |
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| Jul6-12, 09:30 AM | #1 |
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Validity of netwon's laws on the earth's surface
We all know that Newton's laws of motion are only valid in an inertial frame of reference.
Our earth is a rotating frame of reference, so Newton's laws of motion must not work anywhere on the surface of the planet. Do you agree? |
| Jul6-12, 09:44 AM | #2 |
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To include the effects of the earth's rotation, one must modify Newton's laws by the addition of various 'fictitious' forces. (As with any non-inertial frame.) For many purposes, these effects can be neglected and you can treat the earth's surface as being approximately inertial.
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| Jul6-12, 10:13 AM | #3 |
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![]() It's obviously not a frame fixed with respect to the rotating Earth; it's a rotating frame. A non-rotating frame with origin at the center of the Earth doesn't work either. The Earth as a whole is accelerating toward the Sun, the Moon, Jupiter, Venus, etc. How about the International Celestial Reference Frame, the ICRF? It's constructed based on physical measurements so as to be non-rotating, but those measurements aren't perfect. The ICRF almost certainly is rotating by some currently unobservable amount. The ICRF with its origin at the solar system barycenter is an accelerating reference frame; the solar system is orbiting the Milky Way. What about a frame with origin at the center of the Milky Way? The Milky Way is accelerating, too. There is no such thing as a true inertial frame, at least not one that we can find. There are instead frames that are approximately inertial. The ICRF is approximately valid as an inertial frame out to Pluto and beyond. An Earth-centered inertial frame works quite nicely for many Earth-bound applications, but there are times when one needs to account for the frame's acceleration. Even an Earth-fixed frame works quite nicely as an inertial frame for applications in which velocities, relative displacements, and time intervals are small. |
| Jul6-12, 01:54 PM | #4 |
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Validity of netwon's laws on the earth's surface
Thanks for the help!
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| Jul7-12, 11:47 AM | #5 |
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Yes the frame of reference (earth) is spinning all the time, but we are also spinning with it, so we are always in the same position relative to the frame of reference, and this is why we don't see any change, as an observer. The earth is also rotating around the sun, but we are also rotating with it, so we also feel no forces acting upon us, even when there are forces. This is like when astronauts are in free-fall in space. They are not experiencing zero gravity. They are merely falling with their frame of reference, falling along the curve of the earth, similar to how we are falling along the curve of the sun, and along a curved circular path as we spin around on earth's axis. Newton's laws are valid within a frame of reference (relative to that frame of reference). Therefore they will not be affected if there is no change in our motion relative to our frame of reference, so I don't see why they wouldn't be valid on the earth's surface.
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| Jul7-12, 01:52 PM | #6 |
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The answer is both if you create some fictitious forces to account for that perceived acceleration in the rotating frame. BTW, we do feel a force. It's called the tide. These fictitious forces can be a very useful fiction. For example, it would be downright impossible to simulate the weather from the perspective of an inertial frame. |
| Jul7-12, 06:08 PM | #7 |
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Newton's Third Law of Motion (Principia, Law III) states: To every action there is always opposed an equal reaction; or the mutual actions of two bodies upon each other are always equal and directed to contrary parts. Read the third law carefully. According to the Third Law of motion, every force has to be associated with two bodies. If the bodies weren't paired, then the forces couldn't be paired. Consider any body in the surface frame. Neither the centrifugal force nor the Coriolis force has a corresponding body to which a mutual action can be applied. From the standpoint of an inertial frame, the motions caused by these two pseudoforces are caused by a force on the observer, not on another body. Violations in the Third Law are apparent when bodies are unpaired. If a force is exerted on one body and there is not corresponding body to which the opposite force can be applied, then the Third Law is violated. As an example, consider the bob on a Foucault pendulum. At any point except on the equator, the Coriolis force makes the bob precess. However, there is no body corresponding to the bob upon which a mutual force can be applied. In an inertial reference frame, there is no Coriolis force. The apparent motion of the Foucault pendulum doesn't occur. It is due to a force on the observer that is fixed to the surface of the earth. For the POV observer in orbit around the earth, neither centrifugal force nor Coriolis force exists. There are only contact forces and gravitational forces. However, most humans observe from the POV of an local observer fixed to the surface of the earth. Therefore, the third law takes a slight beating in terms of local observation. |
| Jul7-12, 06:17 PM | #8 |
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In the end, one has to subtract the "background motion" of the earth's surface. However, none of this violates Newton's Laws. In actual practice, the problem is simplified if the acceleration of the earth's surface is arbitrarily set to zero. No "background motion" has to be subtracted. The price of this simplification is that the Coriolis force and the centrifugal force has to be set to nonzero values. Thus, this is really a noninertial frame. General relativity complicates this view of nature, somewhat. However, it ends up the same. The surface of the earth is not a geodesic. So Newton's Laws can't be valid even as an approximation from the standpoint of a surface frame. |
| Jul7-12, 11:57 PM | #9 |
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