- #1
pedro_ani
- 2
- 0
Any sugestions on how to find the solutions to this equation?[itex]y'' +\frac{b'}{b} y' - \frac{a^2}{b^2}y=0[/itex]
where [itex]a[/itex] is a constant
where [itex]a[/itex] is a constant
Looks to me that if you substitute that in the original equation there'll be an unbalanced b''' term.bigfooted said:[itex]y=(A\sin(cx)+B\cos(cx))\frac{b'}{2b}[/itex]
There are several methods for solving equations, such as substitution, elimination, and graphing. Choose the method that works best for the specific equation and follow the steps carefully.
If there are variables on both sides of the equation, you can use the properties of equality to move the variables to one side and the constants to the other side. Then, solve for the remaining variable.
Yes, it is always a good idea to check your solution by plugging it back into the original equation. If both sides of the equation are equal, then your solution is correct.
There is no specific order in which you must solve an equation, but it is important to follow the rules of algebra and perform the same operation on both sides of the equation in order to maintain equality.
If the equation contains fractions or decimals, you can eliminate them by multiplying both sides of the equation by the least common denominator (LCD). This will result in a new equation with whole numbers, which can be solved using the methods mentioned in question 1.