Initial velocity


by manimaran1605
Tags: initial, velocity
manimaran1605
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#1
Sep26-13, 08:19 AM
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A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
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ZapperZ
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Sep26-13, 08:29 AM
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Quote Quote by manimaran1605 View Post
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
So you're saying that there's NO difference between just releasing the stone from a stationary balloon that isn't moving? Think again.

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dauto
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#3
Sep26-13, 08:59 AM
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Quote Quote by manimaran1605 View Post
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how?
No, not opposite sign. Same sign.
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
You're free to think whatever you want. That doesn't make it right.

Nugatory
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#4
Sep26-13, 10:24 AM
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Initial velocity


Quote Quote by manimaran1605 View Post
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
Think about that for a moment. When you throw a stone upwards, you release it from your hand while your hand is moving upwards rapidly... What happens?


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