- #1
nophun6
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I have three questions that I think I have the answers to, but would like someone to tell me if I did them correctly. Thanks!
Q1. Given B= 0.8T, a coil with 1 loop with length of 20cm, a current of 5.0A, what are the size and direction of the magnetic force on the loop?
A1. Would I just use Fm= IxBxL = (5A)(.8T)(.2m) = .8 N ?
As for the direction I know it involves the right hand rule, and the current moves to the right, so would the magnetic force be pointing up ?
Q2. What is the magnetic flux through the loop?
A2. Would I use: Flux= ABcos0 = pi(.2)^2 (.8T) (cos0) = .101 Wb ??
Q3. If the magnetic field has a cut off at the top of the loop, and the loop is pulled completely out of the field upwards at v = .2 m/s:
what EMF would be generated and if the resistance was 4 ohms, what would the current be?
A3: EMF= Blv = (.8T)(.2m)(.2m/s) = .032V
O = EMF/R = .032V / 4 ohms = .008Ado these look right? thanks.
Q1. Given B= 0.8T, a coil with 1 loop with length of 20cm, a current of 5.0A, what are the size and direction of the magnetic force on the loop?
A1. Would I just use Fm= IxBxL = (5A)(.8T)(.2m) = .8 N ?
As for the direction I know it involves the right hand rule, and the current moves to the right, so would the magnetic force be pointing up ?
Q2. What is the magnetic flux through the loop?
A2. Would I use: Flux= ABcos0 = pi(.2)^2 (.8T) (cos0) = .101 Wb ??
Q3. If the magnetic field has a cut off at the top of the loop, and the loop is pulled completely out of the field upwards at v = .2 m/s:
what EMF would be generated and if the resistance was 4 ohms, what would the current be?
A3: EMF= Blv = (.8T)(.2m)(.2m/s) = .032V
O = EMF/R = .032V / 4 ohms = .008Ado these look right? thanks.