Calculating Tension in a Cord Attached to an Inclined Crate

  • Thread starter chaotixmonjuish
  • Start date
  • Tags
    Incline
In summary, a wheel with a radius of 10.0 cm is attached to a massless cord that is connected to a 2.00-kg crate sliding down a frictionless inclined surface at an angle of 27.5° with the horizontal. The crate has an acceleration of 3.0 m/s2 and the tension in the cord can be calculated using the equation T=mg-ma. The fact that the wheel has no mass does not affect the calculation.
  • #1
chaotixmonjuish
287
0
A wheel of radius R = 10.0 cm is mounted on a frictionless horizontal axis. A massless cord is wrapped around the wheel and attached to a 2.00-kg crate that slides on a frictionless surface inclined at an angle of 27.5° with the horizontal. The crate accelerates down the incline at 3.0 m/s2. What is the tension in the cord?

Is it possible to still work with this since there is no mass attached to the pulley? I'm pretty sure I need to use a moment of inertia equation to calculate the tension.
 
Physics news on Phys.org
  • #2
Yes, you can do this without knowing the mass of the pulley.
 
  • #3
How does this work? I'm having a few problems.
 
  • #4
You've been given the acceleration of the crate. What's your equation relating the acceleration and tension of the crate (using Newton's second law)?
 
  • #5
F=ma

Would I have to worry about the circle?
 
  • #6
T=mg-ma

T=18.6*sin(27.5)-2*3
 
Last edited:

1. What is tension in a cord?

Tension is the force exerted by a cord or rope when it is pulled tight. It is a result of the external forces acting on the object the cord is attached to.

2. How is tension calculated in a cord attached to an inclined crate?

Tension in a cord can be calculated using the formula T = mgcosθ, where T is the tension, m is the mass of the crate, g is the acceleration due to gravity, and θ is the angle of the incline.

3. What factors affect tension in a cord attached to an inclined crate?

The factors that affect tension in a cord attached to an inclined crate include the mass of the crate, the angle of the incline, and the acceleration due to gravity.

4. How does the angle of the incline affect tension in a cord attached to an inclined crate?

The angle of the incline affects the tension in a cord by changing the vertical and horizontal components of the weight of the crate. As the angle increases, the vertical component decreases and the horizontal component increases, resulting in a higher tension in the cord.

5. Can tension in a cord ever be greater than the weight of the crate?

Yes, tension in a cord can be greater than the weight of the crate if the angle of the incline is steep enough. At a certain angle, the vertical component of the weight of the crate becomes zero, and the entire weight is supported by the tension in the cord.

Similar threads

Newton's Second Law (Pulley Sustem)
    • Introductory Physics Homework Help
Replies
3
Views
774
Acceleration and Tension in a Two-Block System on an Inclined Plane
    • Introductory Physics Homework Help
Replies
8
Views
1K
Question on Moment of Inertia/Rotational Inertia
    • Introductory Physics Homework Help
Replies
4
Views
2K
Swinging Ball at Top of Circle: Forces & Energies
    • Introductory Physics Homework Help
Replies
16
Views
2K
Work done by the force of a man on a crate of 80N
    • Introductory Physics Homework Help
Replies
14
Views
5K
Calculating Coefficient of Friction for a Crate on an Inclined Surface
    • Introductory Physics Homework Help
Replies
2
Views
3K
How Does a Frictionless Incline Affect Crate Acceleration and Wheel Tension?
    • Introductory Physics Homework Help
Replies
2
Views
2K
Friction Problem of a Crate Sliding Down a Ramp
    • Introductory Physics Homework Help
Replies
4
Views
2K
Push a crate up a frictionless incline
    • Introductory Physics Homework Help
Replies
1
Views
3K
Inertia block on inclined surface problem? help with solution?
    • Introductory Physics Homework Help
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top