A functional that depends on an integral?

In summary, the conversation is about whether it is possible to find the extrema of an integral equation with a variable and an integral of that variable as the integrand. The question is whether this is a "nonlocal" functional and if there are any references on this type of problem. One person has tried to apply the Euler-Lagrange equations but was unsuccessful. Another person suggests that the integral can be simplified to ln[integral(f(y,x') dx')] integral(f(y,x) dx) and poses the question whether this is equal to ln[integral(f(y,x) dx)] integral(f(y,x) dx).
  • #1
jfitz
12
0
Is it possible to find the extrema of an integral equation if the integral depends on a variable and an integral of that variable, i.e. the integrand is f(x) * g(integral(x)).

I'm not sure if this is a "nonlocal" functional, or not a functional at all, but I can't find any references that deal with this type of problem.

If anybody has any ideas of where I could find more information about this, please let me know.
 
Physics news on Phys.org
  • #2
In case the question wasn't clear, here it is in a different way:

Does the calculus of variations apply to situations where you're looking for some function, y(x), that extremizes (in my particular case)

[tex]\int{ f(y,x) \ln{ \left[ \int{ f(y,x) dx } \right] } dx }[/tex]

?
 
  • #3
I tried to apply the quick-and-dirty physicist's derivation of the Euler-Lagrange equations to this case but came up empty handed. Maybe it is possible to solve for the particular case of the function f you are interested in, but otherwise I am at a loss for how to proceed.
 
  • #4
jfitz said:
[tex]\int{ f(y,x) \ln{ \left[ \int{ f(y,x) dx } \right] } dx }[/tex]

?

Maybe I'm being stupid but isn't that equal to

[tex]\int{ f(y,x) \ln{ \left[ \int{ f(y,x') dx' } \right] } dx }=\ln{ \left[ \int{ f(y,x') dx' } \right]\int{ f(y,x) } dx }=\ln{ \left[ \int{ f(y,x) dx } \right]\int{ f(y,x) } dx }[/tex]

...?
 

1. What is a functional that depends on an integral?

A functional that depends on an integral is a mathematical concept where a function is defined based on an integral, rather than on a set of values. This means that the function is defined in terms of a range of possible inputs, rather than just specific values.

2. How is a functional that depends on an integral different from a regular function?

A regular function takes specific values as inputs and produces specific values as outputs. However, a functional that depends on an integral takes a range of values as inputs and produces a single value as an output, based on the integral of the function.

3. What is the purpose of using a functional that depends on an integral?

A functional that depends on an integral is often used to model complex systems or processes, where the function cannot be easily described by a regular function. It allows for a more generalized and flexible representation of the system.

4. What is an example of a functional that depends on an integral?

One example is the action functional used in physics, which describes the motion of a physical system by integrating over all possible paths. This allows for a more complete and accurate representation of the system's behavior.

5. Are there any limitations to using a functional that depends on an integral?

While a functional that depends on an integral can provide a more generalized representation of a system, it can also be more complex and difficult to work with compared to regular functions. It may also require advanced mathematical techniques to solve and analyze.

Similar threads

Replies
31
Views
894
  • Calculus
Replies
6
Views
1K
Replies
20
Views
2K
Replies
3
Views
958
Replies
2
Views
908
Replies
4
Views
1K
Replies
33
Views
2K
Replies
1
Views
907
Back
Top