- #1
jumbogala
- 423
- 4
Homework Statement
I know how to take the derivative of ln(x), it's just 1/x. But what if you had something more complicated than just x?
For example, ln(x4(2x+5)5)?
Homework Equations
The Attempt at a Solution
I guess you would still do 1/(x4(2x+5)5), then multiply it by the derivative of the denominator.
Which would be 4x3(2x+5)5 + x4(5(2x+5)4)(2).
Is that correct?
The problem I'm supposed to be doing is actually more complicated, it's ln[x5(x+4)3(x3+4)6]. Would the procedure be similar? I guess I'm not sure about taking the derivative of something with 3 terms, I've only ever seen it done with two.