Nature of the electric field

In summary: Newtonian gravity can be formulated in terms of Gauss's law and both have units of force per unit mass, but electric field has units of force per unit charge while gravity has units of force per unit mass.In summary, the conversation discusses the similarities and differences between the gravitational and electric fields, which both have units of force per unit mass but differ in units of force per unit charge. The concept is further explained through examples and comparisons to Newton's laws and the concept of acceleration. The conversation also acknowledges the complexity of understanding the electric field in terms of simpler units and concepts.
  • #1
diagopod
98
3
I've been learning the basics of Maxwell's laws, and was especially interested to see that there was a Gaussian formulation of Newtonian gravity in terms of the negative divergence of the gravitational field, which in turn helped me understand the divergence of the electric field a bit more clearly. But the gravitational field g is quite straightforward for me to understand, as its simply acceleration, or at least reduces to units of acceleration. E, on the other hand, doesn't seem to have such simple units. Even using Gaussian units, it it's not much clearer to me than SI's Force/charge or Volts/meter, although it's nice not to have Epsilon0 to contend with. In any event, are there any units that treat the E-field in a more conceptually accessible way, like g, as something like acceleration, or velocity? Thanks for any help on this, appreciate it.
 
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  • #2
The electric field is a force which is an acceleration. It is in SI units of Newtons. Newtons per coulomb to be exact. It is conservative just like gravity.
 
  • #3
diagopod said:
... the gravitational field g is quite straightforward for me to understand, as its simply acceleration, ... E, on the other hand, doesn't seem to have such simple units. ... are there any units that treat the E-field in a more conceptually accessible way, like g, as something like acceleration, or velocity?

The two quantities are completely analogous, but you are looking for something that just doesn't work out. The gravitational field is force per unit mass, while the electric field is force per unit charge. Again this is perfectly analogous.

However, gravitation is fundamentally different than electric-static force in that inertial mass is exactly equal to gravitational mass, and cancels out in the equations. This is why the static Newtonian gravitational field is an acceleration field. The best you can do is say that electric field is like ma/q, where m is mass, a is acceleration and q is charge. Gravity is like ma/m, if you want to make the comparison.

To highlight the difference, consider that both an electron and a proton have the same charge magnitude, but something like a factor of 1830 difference in mass. You can't even choose a dimensional unit convention that will work in all cases.

Personally, I think that electric field is very intuitive when thought of as force per unit charge. It represents the force experienced by a test charge. It is also the negative gradient of the voltage, and voltage is potential energy per unit charge, which is also very intuitive, when compared to mechanical equations. (i.e. work is force integrated through a distance)
 
  • #4
elect_eng said:
The best you can do is say that electric field is like ma/q, where m is mass, a is acceleration and q is charge. Gravity is like ma/m, if you want to make the comparison.

Thanks, I see your point. I suppose if force were defined in terms of charge instead of mass, I'd be asking the same question about the gravitational field.
 
  • #5
diagopod said:
Thanks, I see your point. I suppose if force were defined in terms of charge instead of mass, I'd be asking the same question about the gravitational field.

Huh? Force is the change of the change of position, mass is only a coefficient.
 
  • #6
LostConjugate said:
Huh? Force is the change of the change of position, mass is only a coefficient.

Well, technically it's the change in momentum which is related to the change in mass and the change in velocity. However, outside of examples like rocketry, there is no change in mass. But yes, diagopod's comment does not make sense as the the charges that the electrodynamic forces act on have mass to and thus they respond in the same way as a particle does to a gravitational force.
 
  • #7
Born2bwire said:
But yes, diagopod's comment does not make sense as the the charges that the electrodynamic forces act on have mass to and thus they respond in the same way as a particle does to a gravitational force.

True, true, but I should probably clarify what I was trying to say and save a little bit of face :) I meant that if, for example, charge and the laws of electrostatics had been discovered/defined first, and "force" had been defined accordingly not as F = ma, but rather F = qa, and thus not meaning force as we now know it, then the e-field would simply be acceleration and g, once discovered, would adopt the units qa/m, which would be as awkward to me conceptually as I find the e-field to be now (as ma/q). Of course, I'm probably still flubbing it, but just trying to explain what I was trying to say :)
 
  • #8
diagopod said:
True, true, but I should probably clarify what I was trying to say and save a little bit of face :) I meant that if, for example, charge and the laws of electrostatics had been discovered/defined first, and "force" had been defined accordingly not as F = ma, but rather F = qa, and thus not meaning force as we now know it, then the e-field would simply be acceleration and g, once discovered, would adopt the units qa/m, which would be as awkward to me conceptually as I find the e-field to be now (as ma/q). Of course, I'm probably still flubbing it, but just trying to explain what I was trying to say :)

I wouldn't expect that definition to hold water. What about chargeless particles like neutrons? Also acceleration does not retain it's original mathematical formulation here. Electrons and protons have the same amount of charge but are accelerated at different rates in an electric field. How do you account for that?
 
  • #9
diagopod said:
... and save a little bit of face :)

There is no need to save face. We all ask this question when we first contemplate this. This issue kept Galileo, Newton and Einstein busy enough. So you are in good company.

However, you can now crystalize the notion that gravity is very unique and quite amazing in its behavior. Electrostatic force and Newtonian static gravity are very very similar, but there is the fundamental difference that gravitational mass and inertial mass are absolutely identical as far an all experimental evidence indicates. This has the result that the gravitational field can be interpreted as an acceleration field, and nothing can make electrostatic charge exhibit this behavior.

This is not a trivial thing and it is a key concept that led Einstein to general relativity. GR is to Newtonian static gravity, what Maxwell's equations are to electrostatics. GR and Maxwell's Equations are full dynamic classical theories backed by experimental evidence. It is interesting that this so called "equivalence principle" links acceleration and gravity and is a key component to GR.
 
  • #10
It can be fun to play around with different dimensional interpretations to give insight to questions like this, even if they have little practical value.

For instance, if, instead of defining a universal gravitational constant G, one were given a gravitational acceleration formula of the form:

[tex] a_g = \frac{1}{m_2} \frac{m_1 m_2}{r^2}[/tex]

and performed dimensional analysis one might conclude that mass must have dimensions of L^3/T^2 (L = length, T = time).

eg

[tex] L/T^2 = \frac{1}{L^3/T^2} \frac{L^3/T^2 L^3/T^2}{L^2}[/tex]

Now, L^3/T^2 looks like an accelerating quantity of 3D space itself. Is it a coincidence that GR could be interpreted as space flowing into mass?

Likewise, if one were handed a formula for electric acceleration of the form

[tex] a_e = \frac{1}{m_2} \frac{q_1 q_2}{r^2}[/tex]

and taking the previous dimensionality of mass, one might conclude charge has the same dimensions. However, now you have a modifying ratio of charge to mass: q_2/m_2, which would end up being a dimensionless attribute of the particle in question.

A step further would be to recognize that the dimensions of space and time are actually related by the speed of light: L = cT. So, charge and mass could be described by a single dimensional quantity such as L^3/T^2 = c^2L, or just L if you take c =1. Now, this is interesting, since now all fundamental dimensions (charge, mass, time, length) can be reduced to a single dimension, with all the dynamics described by dimensionless quantities (such as electron charge to mass: e/m_e), with all accelerations having dimensions of 1/L, which looks like the dimensions of some type of space/time derivative.

Even a step further would be to ask, given the above assumptions, what are the dimensions of the electric field? If one is given something like

[tex] E = \frac{q}{r^2}[/tex]

the dimensions of E would be

[tex] [E] = \frac{L^3/T^2}{L^2} = L/T^2 = 1/L[/tex]

given the above assumptions, E would have the same dimensions as acceleration, except one would have to keep in mind that it is modified by that dimensionless quantity when acting on a particle.

What about a magnetic field given by something like

[tex] B = \frac{q*v}{r^2}[/tex]

[tex] = \frac{(L^3/T^2)*(L/T)}{L^2} = L^2/T^3 = 1/L [/tex]

Which has the same fundamental dimensionality, again keeping in mind the dynamics would be governed by the dimensionless quantities.

Anyway, just food for thought, take from it what you will.
 
  • #11
kcdodd said:
It can be fun to play around with different dimensional interpretations to give insight to questions like this, even if they have little practical value.

For instance, if, instead of defining a universal gravitational constant G, one were given a gravitational acceleration formula of the form:

[tex] a_g = \frac{1}{m_2} \frac{m_1 m_2}{r^2}[/tex]

and performed dimensional analysis one might conclude that mass must have dimensions of L^3/T^2 (L = length, T = time).

is ag the acceleration of body 2? If so , are you working with natural units? This is fine and all, but natural units are inconsistent with respect to conservation of units. Even in the famous space-time equivalence, units are preserved.
 
  • #12
What I wrote here is not a new idea. If the only difference between two dimensions is a constant, then why even bother defining them to be different. One can see that every quantity can be reduced to a single dimensionality, and every dynamical field can be reduced to the a single dimensionality.
 
  • #13
Born2bwire said:
Well, technically it's the change in momentum which is related to the change in mass and the change in velocity.

Are you saying that F = (m)(d/dt)(v) = (d/dt)(mv) ?
 
  • #14
espen180 said:
I wouldn't expect that definition to hold water.
You're certainly right, it doesn't add up, I was just trying to say that if it had been true then my conceptually misunderstanding would have been reversed. Either way, point taken.
 
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  • #15
elect_eng said:
There is no need to save face. We all ask this question when we first contemplate this.

Thanks, glad to know, appreciate the kind words.

Thanks for the further explanation. Btw, regarding the equivalence of inertial and gravitational mass, when we see precise values for the mass of the electron and proton, did the experiments that derived those values test for gravitational or inertial mass? If inertial, is there any way to test for the gravitational mass of the electron and proton, or can we safely deduce those by extrapolation from the macroscopically confirmed equivalence of i and g mass?
 
  • #16
diagopod said:
Btw, regarding the equivalence of inertial and gravitational mass, when we see precise values for the mass of the electron and proton, did the experiments that derived those values test for gravitational or inertial mass? If inertial, is there any way to test for the gravitational mass of the electron and proton, or can we safely deduce those by extrapolation from the macroscopically confirmed equivalence of i and g mass?

These are good questions, but they are outside my area of expertise. I hope someone else can help answer these questions because I'm curious too. My own guess is that gravitational force from atomic particles is too small, and hence difficult (or maybe impossible) to measure. If I were to try and measure proton and electron mass (either absolute in kg or relative to each other), I would measure inertial mass by using electric or magnetic fields to apply force, and then note the deflection from a straight path.
 
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  • #17
diagopod said:
Thanks, glad to know, appreciate the kind words.

Thanks for the further explanation. Btw, regarding the equivalence of inertial and gravitational mass, when we see precise values for the mass of the electron and proton, did the experiments that derived those values test for gravitational or inertial mass? If inertial, is there any way to test for the gravitational mass of the electron and proton, or can we safely deduce those by extrapolation from the macroscopically confirmed equivalence of i and g mass?

You are entering the domain of Quantum Gravity. There is to date no theory which accurately predicts gravitational effects when quantum effects are important. The reason is that we have not been able to measure anything at this level. Much of the problem lies in probing the gravitational effects, as the gravity of the lab equipment is many orders of magnitude higher than the effect to be measured.
 
  • #18
espen180 said:
You are entering the domain of Quantum Gravity. There is to date no theory which accurately predicts gravitational effects when quantum effects are important. The reason is that we have not been able to measure anything at this level. Much of the problem lies in probing the gravitational effects, as the gravity of the lab equipment is many orders of magnitude higher than the effect to be measured.

Thanks, that makes sense to me. Can I safely deduce from this the values of the electron and proton mass that we currently have are measures of inertial mass?
 
  • #19
diagopod said:
Thanks, that makes sense to me. Can I safely deduce from this the values of the electron and proton mass that we currently have are measures of inertial mass?

I think you can, with great certainty, assume they are. Most masses on a small scale are measured with some type of spectrometry, which uses electromagnetic fields.

However, as far as we know, intertial mass = gravitational mass, at least on large scales. (I'm assuming "large" here is on about the scale of a proton, by which quantum effects are very small.)
 
  • #20
espen180 said:
I think you can, with great certainty, assume they are. Most masses on a small scale are measured with some type of spectrometry, which uses electromagnetic fields.

However, as far as we know, intertial mass = gravitational mass, at least on large scales. (I'm assuming "large" here is on about the scale of a proton, by which quantum effects are very small.)

Thanks, appreciate your help on this.
 
  • #21
LostConjugate said:
Are you saying that F = (m)(d/dt)(v) = (d/dt)(mv) ?

Technically,
[tex] \mathbf{F} = \frac{d}{dt} \left(m\mathbf{v}\right) = m\frac{d\mathbf{v}}{dt}+\mathbf{v}\frac{dm}{dt} [/tex]

The mass is pretty much a constant in most given problems but there can be problems where it is changing due to the shedding of fuel. For example, a rocket's mass decreases as its fuel is consumed.
 

1. What is the nature of the electric field?

The electric field is a fundamental concept in physics that describes the force exerted by an electric charge on other charges. It is a vector quantity, meaning it has both magnitude and direction, and is generated by the presence of electric charges. The electric field is responsible for many phenomena, such as electricity, magnetism, and light.

2. How is the electric field generated?

The electric field is generated by the presence of electric charges. When a charged particle is placed in a region, it creates an electric field around it. The direction of the electric field is determined by the sign of the charge, with like charges repelling each other and opposite charges attracting each other.

3. What is the difference between electric field and electric potential?

The electric field and electric potential are related but distinct concepts. The electric field describes the force exerted by an electric charge, while the electric potential describes the potential energy of a charge in an electric field. In other words, the electric field is the cause of the electric potential.

4. How is the strength of the electric field measured?

The strength of the electric field is measured by its magnitude, which is given in units of Newtons per Coulomb (N/C). This represents the amount of force experienced by a test charge placed in the electric field. The direction of the electric field is also important, and it is represented by the direction of the force on a positive test charge.

5. What are some real-world applications of the electric field?

The electric field has many practical applications in our daily lives. Some examples include electricity generation and distribution, electronics and circuitry, and the behavior of charged particles in medical devices such as MRI machines. The electric field also plays a crucial role in understanding and predicting natural phenomena such as lightning and the aurora borealis.

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