- #1
flyingpig
- 2,579
- 1
Homework Statement
Solve for all x that satisifies
[tex]log_{0.5} \frac{2x - 5}{x + 2} < 0[/tex]
The Attempt at a Solution
Let me just say that upon doing this problem i learned that
1) When you exponeitate something to the base in (0, 1), you flip the inequality sign.
So I finally got the solution to be (-infy,-2) U (7, infty)
Now i found that this approach does not work
[tex]log_{0.5} \left | \frac{2x - 5}{x + 2} \right | < 0[/tex]
SO it would make sense that
[tex]\left | \frac{2x - 5}{x + 2} \right | < 0[/tex]
Okay after doing some test points for
[tex]\frac{2x - 5}{x + 2} < 0[/tex]
[tex]\frac{5 - 2x}{x + 2} > 0[/tex]
I found that there are no solution to the absolute value ...
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