How to Determine the Empirical Formula of a Compound?

[k3l]

1.324g of compound C(x)H(y)Cl(z) was split into two samples of equal mass. Burning the first gave 1.189g of CO(2). Treating the second gave 1.292g of silver chloride. if the relative molecular mass is 147 determine;
the Empirical Formula? (ie. find x, y and z)

thx

 

[chem_tr]

In our policy, we don't solve the whole question for yourself; just show us your effort on what point you've came and stuck.

 

[ravenprp]

To determine the empirical formula of compound C(x)H(y)Cl(z), we can use the given information and the concept of the empirical formula. The empirical formula is the simplest ratio of atoms present in a compound, so we need to find the ratio of C, H, and Cl atoms in the compound.

First, we need to find the number of moles of each product formed in the reactions. We can use the molar mass of CO2 and AgCl to convert the given masses into moles.

1.189 g of CO2 is equal to 0.027 moles (1.189 g / 44.01 g/mol)
1.292 g of AgCl is equal to 0.0077 moles (1.292 g / 167.87 g/mol)

Next, we can use the mole ratios of the products to determine the number of moles of C, H, and Cl atoms in the compound.

For CO2, there is 1 mole of C for every 1 mole of CO2.
Therefore, there are 0.027 moles of C in the compound.

For AgCl, there is 1 mole of Cl for every 1 mole of AgCl.
Therefore, there are 0.0077 moles of Cl in the compound.

Now, to find the number of moles of H, we can subtract the moles of C and Cl from the total number of moles of the compound (0.027 - 0.0077 = 0.0193). This means there are 0.0193 moles of H in the compound.

To find the ratio of C, H, and Cl atoms, we can divide the number of moles by the smallest number of moles (0.0077).

C: 0.027 / 0.0077 = 3.51
H: 0.0193 / 0.0077 = 2.5
Cl: 0.0077 / 0.0077 = 1

Therefore, the empirical formula of the compound is C3.51H2.5Cl. To get whole numbers, we can multiply each ratio by 2, giving us an empirical formula of C7H5Cl2.

In conclusion, the empirical formula of compound C(x)H(y)Cl(z) is C7H5Cl2. This means that for every 7 mo